All categories

3 years ago

This image shows a square pyramid.

Mathematics

2 answers:

AURORKA [14]3 years ago

5 0

Answer:

128

Step-by-step explanation:

I just took the test and I can confirm that this answer is correct! :D

Lynna [10]3 years ago

3 0

We know that

[Surface area ]=[the area of 4 triangles]+[the area of square base]
[the area of square base]=8*8--------> 64 ft²

[the area of 1 triangle]=(1/2)*b*h
b=8 ft
How the angle is 45°-------> h=b/2-------> h=4 ft
then
[the area of 1 triangle]=(1/2)*8*4------> 16 ft²
and
[the area of 4 triangles]=4*16--------> 64 ft²

[Surface area ]=[64 ft²]+[64 ft²]----------> 128 ft²

the answer is 128 ft²

You might be interested in

To find the extreme values of a function f(x,y) on a curve xequalsx(t), yequalsy(t), treat f as a function of the single vari

pychu [463]

Answer:

Absolute maximum is 2

Absolute minimum at -2

Step-by-step explanation:

The given parametric functions are:

$x=2\cos t,y=2\sin t$

By the chain rule:

$f'(t)=\frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$\frac{df}{dt} =\frac{2 \cos t}{-2\sin t} =-\cot(t)$

At fixed points, $f'(t)=0$

$\implies -\cot (t)=0$

This gives $t=\frac{\pi}{2} ,\frac{3\pi}{2}$ on $0\le t\le 2\pi$

This implies that the extreme points are $(2\cos \frac{\pi}{2}, 2\sin \frac{\pi}{2})=(0,2)$ and $(2\cos \frac{3\pi}{2}, 2\sin \frac{3\pi}{2})=(0,-2)$

By eliminating the parameter, we have $x^2+y^2=4$

This is a circle with radius 2, centered at the origin.

Hence (0,2) is an absolute maximum ,at $t=\frac{\pi}{2}$ and (0,-2) is an absolute minimum at $t=\frac{3\pi}{2}$

7 0

3 years ago

66.64 rounded to the nearest cent

Zolol [24]

It would just be 66.6

4 0

2 years ago

HURRY will mark brainliest <br>which one of the following graphs is not a function?? :)

bonufazy [111]

Answer:

I think its A i'm sorry if its wrong

Step-by-step explanation:

5 0

3 years ago

X2 +5x+1<br> x 3x2 - 2x + 4

bulgar [2K]

Answer:

6x^2+5x+4

Step-by-step explanation:

hope this helps

5 0

2 years ago

The constant of proportionality is always the point___________, where k is the constant of proportionality

TiliK225 [7]

Let's take as example a linear function of the form:
y = kx.
Where,
k is the constant of proportionality.
Therefore, the proportionality constant is the point:
(x, kx)
Generically it is always the point:
(x, k * f (x))
Where, f (x) is a function proportional to x.
answer:
The constant of proportionality is always the point (x, k * f (x)), where k is the constant of proportionality.

4 0

3 years ago