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3 years ago

What’s up solution should be used to rewrite 16(x^3+1)^2-22(x^3+1)-3=0

Mathematics

1 answer:

ladessa [460]3 years ago

3 0

Answer:

x = cuberoot( -9/8)= -1.04004 or x = cuberoot(1/2)=0.7937

Step-by-step explanation:

let y = x^3 + 1

we have:

16*(y) ^2 - 22 (y) - 3 = 0

16 = 2* 8

-3 = -3* 1

8*-3 + 2 = -24 + 2 = -22

Factor as (8y + 1)(2y - 3) = 16 (y)^2 - 22(y) - 3 = 0

so (8y + 1) = 0 or 2y - 3 = 0

y = -1/8 OR y = 3/2

with y = x^3 + 1

solve for x

-1/8 = x^3 + 1

x^3 = - 9/8

x = cuberoot( -9/8)

about x = -1.04004

or 3/2 = x^3 + 1

1/2 = x^3

x = cuberoot( 1/2 ) = 0.7937

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Marat540 [252]

Answer:

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Step-by-step explanation:

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Here for constructing 95% confidence interval we have used One-sample z test for proportions.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

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P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

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= [0.169 , 0.331]

Therefore, 95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

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3 years ago

If there is 520 grams of radioactive material with a half-life of 12 hours, how much of the radioactive material will be left af

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Source:
http://www.1728.org/halflife.htm

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