What’s up solution should be used to rewrite 16(x^3+1)^2-22(x^3+1)-3=0
1 answer:
Answer:
x = cuberoot( -9/8)= -1.04004 or x = cuberoot(1/2)=0.7937
Step-by-step explanation:
let y = x^3 + 1
we have:
16*(y) ^2 - 22 (y) - 3 = 0
16 = 2* 8
-3 = -3* 1
8*-3 + 2 = -24 + 2 = -22
Factor as (8y + 1)(2y - 3) = 16 (y)^2 - 22(y) - 3 = 0
so (8y + 1) = 0 or 2y - 3 = 0
y = -1/8 OR y = 3/2
with y = x^3 + 1
solve for x
-1/8 = x^3 + 1
x^3 = - 9/8
x = cuberoot( -9/8)
about x = -1.04004
or 3/2 = x^3 + 1
1/2 = x^3
x = cuberoot( 1/2 ) = 0.7937
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