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2 years ago

The coefficients corresponding to k=0,1,2,5 in the expression (x+y)^5 are

Mathematics

1 answer:

Setler [38]2 years ago

8 0

Answer:

Step-by-step explanation: you got trolded

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How do you do this problem

Ainat [17]

So the problem has no symbols, but we're going to multiply because the fraction on the left is right next to the parentheses.

-5/2 * 1/10x = -5x/20

I put "x" next to the 5 because the "x" counts as part of the numerator. Now that it's 5x over 20 that equals one, I'd first reduce -5x/20 into -x/4, then do

-x/4 * -4 = 1 * -4

To make the "x" side equal one, we have to multiply both sides by -4, to make both sides equal.

x = -4.

4 0

3 years ago

Find the missing length indicated <br>thank yall for helping!

marusya05 [52]

Set up a proportion.

The total side of the “top” line is 8 + 10 = 18. The total side of the “bottom” line is 45. This makes the ratio 18/45.

Now we are trying to find the “larger” bottom segment, let it be x. Because the lines are parallel, the ratio of the “larger” top and bottom segments is equal to the ratio of the whole top and bottom lines.

So 18/45 = 10/x

Reduce 2/5 = 10/x

Cross multiply 2x = 50

Solve x = 25

8 0

2 years ago

Mark mowed 3 lawns in 1 hour how many lanws could he mow in 4 hour

Bond [772]

He can mow 12 lawns in 4 hours.
to get the answer you just multiply the amounts of lawns he mowed by the hours it’s asking.

6 0

3 years ago

Read 2 more answers

A student is trying to solve the set of two equations given below: Equation A: x + z = 6 Equation B: 3x + 2z = 1 Which of the fo

solong [7]

A) multiply equation A by -2 so you get -2x - 2z = -12 and then you can add both equations to eliminate z

8 0

3 years ago

Read 2 more answers

Use the Parabola tool to graph the quadratic function. f(x)=2x^2−12x+19 Graph the parabola by first plotting its vertex and then

Debora [2.8K]

To find the vertex of our parabola, we are going to use the vertex formula: For a quadratic of the form $f(x)=x^2+bx+c$ it vertex $(h,k)$ is given by $h= \frac{-b}{2a}$ , $k=f(h)$ .
We can infet from our parabola that $a=2$ and $b=-12$ . So lets replace those values in our formula:
$h= \frac{-b}{2a}$
$h= \frac{-(-12)}{2(2)}$
$h= \frac{12}{4}$
$h=3$
$k=f(h)=2(3)^2-12(3)+19$
$k=2(9)-36+19$
$k=18-17$
$k=1$
The vertex $(h,k)$ of our parabola is $(3,1)$

Now to find our second point, we are going to evaluate our parabola at $x=0$
$f(0)=2(0)^2-12(0)+19$
$f(0)=0+0+19$
$f(0)=19$
Our second point is $(0,19)$

We can conclude that we can graph the parabola $f(x)=2x^2-12x+19$ using its vertex $(3,1)$ and the point $(0,19)$ as follows:

7 0

3 years ago