The ratio of the surface areas of similar solids is equal to the square of their scale factor and that the ratio of their volumes is equal to the cube of their scale factor.
Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Randy needs to purchase 1.49 Gallons of paint to cover 100 sq. feet wall.
What is the area of rectangle?
The area of a rectangle is the product of its length and width. That is, A = l x w where l is the length and w is the width of the rectangle.
Here, Required Paint = 
= 5 X 37 - 36
= 185 - 36
= 149
= 1.49 gallons
Thus, Randy needs to purchase 1.49 Gallons of paint to cover 100 sq. feet wall.
Learn more about Area of Rectangle from :
brainly.com/question/20693059
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Answer:
10.4 to nearest tenth.
Step-by-step explanation:
If we draw lines from the centre of the circle to each vertex of the hexagon we get 6 equilateral triangles of side length 2.
Altitude of each triangle = sqrt(2^2 - 1^2)
= sqrt3.
So the area of 1 triangle = 1/2 * 2 * sqrt3
= sqrt3
Therefore the area of the hexagon = 6 * sqrt3
= 6sqrt3
= 10.3923
