let the other number be " n "
now, according to above condition :
therefore, the other number would be 23.
Answer: 15 boxes
Step-by-step explanation:
From the question, we are informed that Denise wants to cover a 21.75 square foot wall with weathered wood and that each box of weathered wood contains 1.5 square feet of wood.
The number of boxes of weathered wood that she need will be calculated by dividing 21.75 square feet by 1.5 square feet. This will be:
= 21.75/1.5
= 14.5
= 15 boxes approximately
Total hours= 2.2+3.5=5.7
Total earned = 5.7 x $7.50= $42.75
Set each expression from the parentheses equal to 0 separately like so:
Equation 1: x - 4 = 0
Equation 2: -5x + 1 = 0
Now for each equation solve for x!
Equation 1:
x +(- 4 + 4) = 0 + 4
x = 4
Equation 2:
-5x +( 1-1) = 0 - 1
-5x/ -5 = -1 / -5
x = 1/5
Check:
(4 - 4)(-5*4 + 1)
(0) (-20 + 1)
(0) (-19)
0 = 0 -------------------------> correct!
(1/5 - 4)(-5 * 1/5 + 1)
(-19/5)(-1 + 1)
(-19/5)(0)
0 = 0 -------------------------> correct!
smaller x = 1/5
larger x = 4
Hope this helped!
Answer:
Option 3. 71 ft. is the distance between B and top of the hill.
Step-by-step explanation:
Let the height of the hill is h ft and the distance of A from the hill be x ft and distance from B to hill is y.
It is given distance between A and B is 45 ft. ∠BAO = 65° and ∠ABO = 80°.
We have to find the distance of B from the top of the hill.
Now from ΔACO ![tan 65 = \frac{h}{45-x} = 2.14](https://tex.z-dn.net/?f=tan%2065%20%3D%20%5Cfrac%7Bh%7D%7B45-x%7D%20%3D%202.14)
![h=2.14(45-x)](https://tex.z-dn.net/?f=h%3D2.14%2845-x%29)
From ΔBCO ![tan80 = \frac{h}{x} = 5.67](https://tex.z-dn.net/?f=tan80%20%3D%20%5Cfrac%7Bh%7D%7Bx%7D%20%3D%205.67)
h = 5.67x
Now h = 5.67x = 2.14(45-x)
5.67x = 96.3 - 2.14x
2.14x + 5.67x = 96.3
7.81x = 96.3
x = 96.3/7.81 = 12.33 ft
Therefore ![cos80 = \frac{x}{OB}](https://tex.z-dn.net/?f=cos80%20%3D%20%5Cfrac%7Bx%7D%7BOB%7D)
![0.174 = \frac{12.33}{OB}](https://tex.z-dn.net/?f=0.174%20%3D%20%5Cfrac%7B12.33%7D%7BOB%7D)
![OB = \frac{12.33}{.174}=70.86=71ft.](https://tex.z-dn.net/?f=OB%20%3D%20%5Cfrac%7B12.33%7D%7B.174%7D%3D70.86%3D71ft.)
Therefore 71 ft is the distance between B and the top of the hill.