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jok3333 [9.3K]
3 years ago
12

What is the domain of the function f (x) x-5/x^2-9

Mathematics
2 answers:
dexar [7]3 years ago
8 0

Answer:

its D on edg

Step-by-step explanation:

follow my ifunny "dankmemehistory"

nikklg [1K]3 years ago
7 0
Means the number you can use
remember we can't divide by zero
domain is x^2-9
set to zero to find values we can't use
x^2-9=0
x^2=9
x=+/-3

domain=all real numbers except -3 and 3

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Which process will transform Figure H onto Figure K?
posledela

Answer:

Last option (bottom right)

Step-by-step explanation:

Rotate figure H 180° about the origin, then the figure will turn upside down and will be at quadrant 4, then translating it to 2 units right, you'll get figure K

Answered by GAUTHMATH

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3 years ago
An adult house cat could be about ____ high. A. 1 inch B. 1 foot C. 4 inches D. 4 feet
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The answer is B. 1 foot
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The average production cost for major movies is 57 million dollars and the standard deviation is 22 million dollars. Assume the
Degger [83]

Using the normal distribution, we have that:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).
  • 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
  • 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem, the parameters are given as follows:

\mu = 57, \sigma = 22, n = 17, s = \frac{22}{\sqrt{17}} = 5.3358

Hence:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).

The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:

X = 58:

Z = \frac{X - \mu}{\sigma}

Z = \frac{58 - 57}{22}

Z = 0.05.

Z = 0.05 has a p-value of 0.5199.

X = 55:

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 57}{22}

Z = -0.1.

Z = -0.1 has a p-value of 0.4602.

0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

For the sample of 17 movies, we have that:

X = 58:

Z = \frac{X - \mu}{s}

Z = \frac{58 - 57}{5.3358}

Z = 0.19.

Z = 0.19 has a p-value of 0.5753.

X = 55:

Z = \frac{X - \mu}{s}

Z = \frac{55 - 57}{5.3358}

Z = -0.38.

Z = -0.38 has a p-value of 0.3520.

0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0
1 year ago
Let f(x)=18/1+3^e-0.1x What is the point of maximum growth rate for the logistic function f(x)? Show all work. Round your answer
xz_007 [3.2K]

Answer:

(0, 4.5)

Step-by-step explanation:

*The equation can be put into Desmos, to find the point, but the work to prove it is here*

f(x)=c/1+Ae^-Bx

Y=C

C=18      A=3      -B=-0.1

*Replace x with 0 in the equation, so you know 0 is the x value, and it leads you to the y value*

f(0)=18/1+3e^-o.1(0)

= 18/1+3e^0

=18/1+3(1)

=18/1+3

=18/4

=4.5

x=0    y=4.5

Maximum growth rate = (x,y) --> (0, 4.5)

Hope this helps:))!!

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2 years ago
Becky put $100 into in the account to use for school expenses. The account earns 11% interest, compounded annually. How much wil
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Answer: $187 will be in the account after 6 years.

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = $100

r = 11% = 11/100 = 0.11

n = 1 because it was compounded once in a year.

t = 6 years

Therefore,.

A = 100(1 + 0.11/1)^1 × 6

A = 100(1 + 0.11)^6

A = 100(1.11)^6

A = $187

5 0
3 years ago
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