(HoG)(x) = (2x)2 + 4 simply because HoG(x) is actually H(G(x)). So where ever there was an x in H(x) we substitute our value of G(x). Now the only thing left is to put in the 1. so out answer is (2(1))2 + 4 = 8Only in the 6th grade ; )
Answer:
When two triangles are congruent they will have exactly the same three sides and exactly the same three angles. The equal sides and angles may not be in the same position (if there is a turn or a flip), but they are there.
Take half of the coefficient of x (which is 2/5) and square it:
[ (1/2)(2/5) ]^2 = (1/5)^2 = 1/25, or 0.04
Thus, to rewrite x^2 + (2/5)x to include a perfect square trinomial,
x^2 + (2/5)x = x^2 + (2/5)x + (1/5)^2 - (1/5)^2, or
(x+1/5)^2 - (1/5)^2, or (x + 1/5)^2 - 1/25
6x+1 = 3(2x-4)
-4(x+3) = 4(x-1)
3x+15x = 180
18x = 180
x = 10
10(x+y) + 3x = 180
10x + 10y + 3x = 180
13x + 10y = 180
13(10) + 10y = 180
130 + 10y = 180
10y = 50
y = 5
