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Stells [14]
3 years ago
5

What is 9/1 times 7/10

Mathematics
1 answer:
Grace [21]3 years ago
6 0

To multiply two fractions:

-- Multiply their numerators; the product is the numerator of the new fraction.

9 x 7 = 63 ; the new fraction is (63) / (something)

-- Multiply their denominators; the product is the denominator of the new fraction.

1 x 10 = 10 ;  the new fraction is  <em>63/10</em> .

The product of the two original fractions is  63/10 , or  <em>6.3</em>  .

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3 years ago
Please help me with these two questions
melisa1 [442]

Hi! It will be a pleasure to help you finding the solution to this problem, so let's solve each part:

<h2>PART 1.</h2><h3>Finding the correct expression.</h3><h3>Correct answer:</h3>

\boxed{A. \ 1.50h+4}

From the problem, we know the following data of the problem:

  • Laval parked at the beach.
  • Laval paid a fixed price of $4 for a pass.
  • Laval paid $1.50 for each hour.

Our goal is to find the the expression for the total cost for parking at the beach for h hours. So:

Step 1: Since we have a fixed price, this value will appear in our expression:

4

Step 2: Since Laval paid $1.50 for each hour, this can be represented as the following expression:

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Finally, we can write total cost (C) as the sum of these two expressions:

C=1.50h+4

Finally, our correct option is A:

\boxed{1.50h+4}

<h2>PART 2.</h2><h3>Finding h.</h3><h3>Correct answer:</h3>

5 hours

Here we have to find how many hours Laval spent at the beach knowing that he paid a total amount of $11.50. From the previous part, we know that our expression is:

C=1.50h+4 \\ \\ For \ C=11.50 \\ \\ 11.50=1.50h+4 \\ \\ Subtracting \ 4 \ from \ both \ sides: \\ \\ 11.50-4=1.50h+4-4 \\ \\ 7.5=1.50h \\ \\ Dividing \ both \ sides \ by \ 1.50 \\ \\ h=\frac{7.5}{1.50}=5

Finally, he spent 5 hours at the beach

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3 years ago
Most graduate business schools require applicants to take the gmat. scores on this test are approximately normally distributed w
Harman [31]
We are looking for the probability :
P(X > n)=0.05
Transform the law to standard normal like this:
P(\dfrac{X-545}{100}> \dfrac{n-545}{100})=0.05
The above formula is equivalent to this one:
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\dfrac{X-545}{100}=1.7
Solving the above equation for the score n:
X-545=170
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