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inessss [21]
3 years ago
15

Which value gives the number of particles in 1 mol of a substance? 6. 02 mc012-1. Jpg 1021 6. 02 mc012-2. Jpg 1022 6. 02 mc012-3

. Jpg 1023 6. 02 mc012-4. Jpg 1024.
Mathematics
1 answer:
Nikolay [14]3 years ago
4 0
<h2>Answer:</h2>

The number of particles in 1 mol of substance is given by the Avogadro's constant. Its value is: N_A= 6.02214076×10²³ mol⁻¹

<h2>Explanation:</h2>

The definition of Avogadro's constant is:

The Avogadro constant is the proportionality factor that relates the number of constituent particles in a sample with the amount of substance in that sample. Its SI unit is the reciprocal mole, and it is defined exactly as

N_A= 6.02214076×10²³ mol⁻¹. (per mol).

Thus, the number of particles in 1 mol of substance is given by the Avogadro's constant. Its value is: N_A= 6.02214076×10²³ mol⁻¹

Learn more here:

brainly.com/question/1445383

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Answer:

336 version

Step-by-step explanation:

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6 0
4 years ago
What is the slope of the line that is perpendicular to the line that goes through the two points (-8, 3) and (4, 27)?
Mademuasel [1]

Answer:

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Step-by-step explanation:

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24 / 12 = 2

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8 0
3 years ago
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Step-by-step explanation:

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The largest frog in the world is the goliath,found in west africa. It can grow to be 12 inches long. The smalest in the world is
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Answer:

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Step-by-step explanation:

Given: The largest frog in the world is goliath which is 12 inches long.

           The smallest frog is about 2.5 as long as the goliath.

Lets assume the length of smallest frog be "x".

As given, smallest frog is about 2.5 as long as the goliath.

∴ we can form equation as 2.5x= 12\ inches

Solving the equation to find the value of x

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Dividing both side by 2.5

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So you get y^2+x^2=32, and from there, since we know x and y are equal, you can just divide 32 by 2 then take the square root of that, so the answer should be <em><u>4</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>both</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>y</u></em>

Step-by-step explanation:

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