0.5b>-6 or 3b+16<-8+b solve compound inequality

Mathematics

1 answer:

Basile [38]3 years ago

7 0

0.5b>-6
b>-12

or

3b+16<-8+b
3b<24+b
2b<24
b<12

b>-12 or b<12

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Given that,

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$\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}$