The domain is -5, -4, 1, 2, 4
The sum of any two rational numbers is a rational number, so it's true.
<h2>Answer</h2>
2
<h2>Explanation</h2>
First, we are going to use the law of fractional exponents: ![a^{\frac{1}{n} =\sqrt[n]{a}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%20%3D%5Csqrt%5Bn%5D%7Ba%7D)
We can infer form our expression that
and
, so let's replace the values:
![a^{\frac{1}{n} =\sqrt[n]{a}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%20%3D%5Csqrt%5Bn%5D%7Ba%7D)
![16^{\frac{1}{4} }=\sqrt[4]{16}](https://tex.z-dn.net/?f=16%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%3D%5Csqrt%5B4%5D%7B16%7D)
Notice that we can also decompose 16 into prime factors to get
, so we can rewrite our expression as follows:
![\sqrt[4]{16}=\sqrt[4]{2^4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%3D%5Csqrt%5B4%5D%7B2%5E4%7D)
Finally, we can use the rule of radicals:
, so:
![\sqrt[4]{2^4}=2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%5E4%7D%3D2)
Answer:


Step-by-step explanation:

Substitute
and
back into the equations.


We cannot find
and
as we don't have enough information.
Answer:
b. (10,10,0)
Step-by-step explanation:
r+v can be evaluated if the vectors/matrices have the same dimensions.
These do. They are both 1 by 3 vectors.
Just add first to first in each.
Just add second to second in each.
Just add third to third in each.
Example:
(5,-5,6)+(1,2,3)
=(5+1,-5+2,6+3)
=(6,-3,9)
Done!
In general, (a,b,c)+(r,s,t)=(a+r,b+s,c+t).
r+v
=(7,3,9)+(3,7,-9)
=(7+3,3+7,9+-9)
=(10,10,0)
Done!