Answer:
x=60.9°
Step-by-step explanation:
Given that the height of ball from the ground is 150ft
The base of the pole with the ball is 80 ft from where Trey is standing
Trey's horizontal line of sight is 6 feet above ground, then;
The height of ball from Trey's horizontal line of sight is;
150ft-6ft = 144ft
To find the angle x, assume a triangle with a base of 80 ft , a height of 144 ft and a slant height that represent the line of sight at an angle x
To get angle x , you apply the tangent of an angle formula where;
tan Ф°= length of opposite site of the angle/length of the adjacent side of the angle
tan x°= 144/80
tan x°= 1.8
x°= tan⁻(1.8)
x°=60.9°
X(u, v) = (2(v - c) / (d - c) + 1)cos(pi * (u - a) / (2b - 2a))
y(u, v) = (2(v - c) / (d - c) + 1)sin(pi * (u - a) / (2b - 2a))
As
v ranges from c to d, 2(v - c) / (d - c) + 1 will range from 1 to 3,
which is the perfect range for the radius. As u ranges from a to b, pi *
(u - a) / (2b - 2a) will range from 0 to pi/2, which is the perfect
range for the angle. So, this maps the rectangle to R.
6x - 9x - 5 =
combine like terms
6 - 9 = - 3
- 3x - 5 =
leave x by itself
- 3x - 5 =
+3x
___
0
- 5 = 3x
solve for x (division)
- 5 = 3x
___
3
-5/3 = x OR x = -5/3
Answer:
-18
Step-by-step explanation:
A is at -30. AE = 12
So, E is -30+12 = -18
