<h2>
Explanation:</h2>
Use BODMAS and algebra to arrive at the values of P = 5/2, q = -25/4 and r = -9/2.
Then substitute the values of p and q into p+2q to get -10
Answer:
x = 4/3
y = 1/3
Step-by-step explanation:
System of equations! This is set up really well to make the second equation equal x then substitute.
x - y = 1
x = 1 + y
and then our substitution:
2 (1+y) + y = 3
and solve:
2 + 2y + y = 3
3y + 2 = 3
3y = 1
y = 1/3
And now we can substitute that value into one of our equations:
x - (1/3) = 1
x = 4/3
Next we should check by substituting these values into both of our equations:
2 (4/3) + (1/3) = 3
9 / 3 does equal 3 !
(4/3) - (1/3) does equal 1 !
Therefore, x = 4/3 , and y = 1/3
Answer:
Step-by-step explanation:
Given system of equations:
To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:
Factor the quadratic:
Apply the <u>zero-product property</u> and solve for x:
Substitute the found values of x into the <u>second equation</u> and solve for y:
Therefore, the solutions are:
\left[x \right] = \left[ 3\right][x]=[3] totally answer
