the following data give the hours spent studying per week by nine students. 12, 16, 7, 22, 11, 18, 7, 25, 16. (a) find the mean,
1 answer:
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Answer:
0.9209
Explanation:
For a normally distributed random variable, the only way to find areas is using the z score. The z score is given by the equation:
Where μ is the mean, σ is the standard deviation and x is the raw score to be measured.
The area under the standard normal curve that lies between the interval z=-2.73 and z=-1.39
From the z table, Area between -2.73 and -1.39 = P(z < -1.39) - P(z < -2.73) = 0.0823 - 0.0032 = 0.0791
Since the Area between -2.73 and -1.39 is 0.0791, the are outside the interval = 1 - 0.0791 = 0.9209
The expression is a product expression
The denominator of the simplified fraction is 3n -2
<h3>How to determine the denominator?</h3>The expression is given as;
Divide the first fraction by 2/2
Evaluate the above product
The above fraction is a simplified fraction of , and the denominator is 3n - 2
Hence, the denominator of the simplified fraction is 3n -2
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