Answer:
For a trapezium of height H, parallel side 1 X, and parallel side 2 Y, the area is:
A = (1/2)*H*(X + Y)
with this we can complete the table.
a)
Here we know:
X = 7cm
Y = 11cm
H = 6cm
Then: A = (1/2)*6cm*(7cm + 11cm) = 54 cm^2
b)
Here we know:
X = 8 m
Y = 10 m
A = 126 m^2
Then:
126 m^2 = 0.5*H*(8m + 10m)
126 m^2 = H*9m
126 m^2/9m = H = 14m
Then the height of this trapezoid is 14m
c)
Here we know:
X = 5mm
H = 8mm
A = 72 mm^2
Then:
72 mm^2 = 0.5*8mm*(5mm + Y)
72 mm^2 = 4mm*(5mm + Y)
72mm^2/4mm = 5mm + Y
18 mm = 5mm + Y
18mm - 5mm = Y
13 mm = Y
Then the parallel side 2 is 13 mm long.
Answer:
sin A = 15/17
sec A = 17/8
Step-by-step explanation:
15 cot A = 8
First get cot A alone.
cot A = 8 / 15
Since cot is the reciprocal of tan then flip 15 and 8.
tan A = 15 / 8
Now you have the opposite and adjacent sides, just find the hypotenuse with Pythagorean's theorem
15^2 + 8^2 = 289
= 17
Now that you have all the sides use the opposite and hypotenuse to get sine and the adjacent and hypotenuse to get cosine then flip to get secant.
sin A = 15/17
cos A = 8/17
sec A = 17/8
Answer:
a = 6, b = -2, c = 3
Step-by-step explanation:
6x² - 2x + 3 = 0
a = 6, b = -2, c = 3
40 x 100L which is wrong but i need points
2 and 1/2=2.5cups
2.5 times 16=40tablespoons
1.5g=1tbs
1.5 times 40=60
60 grams
