Question

Use the distance formula d= √ (x2-x1)^2+(y2-y1)^2 to find the length of the line with endpoints at (1,3) and (3,1)?

Answer 1

We have that
line with endpoints at (1,3) and (3,1)

we know that

Applying the distance formula
d= √ (x2-x1)^2+(y2-y1)^2
d= √ (3-1)^2+(1-3)^2-------> d=√[2²+(-2)²]-----> d=√8