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3 years ago

Use the distance formula d= √ (x2-x1)^2+(y2-y1)^2 to find the length of the line with endpoints at (1,3) and (3,1)?

1 answer:

6 0

We have that
<span>line with endpoints at (1,3) and (3,1)

we know that

Applying </span><span>the distance formula
d= √ (x2-x1)^2+(y2-y1)^2
</span>d= √ (3-1)^2+(1-3)^2-------> d=√[2²+(-2)²]-----> d=√8

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d1i1m1o1n [39]

No, because it has a constant rate of change

By looking at this table

The y value changes at a constant multiple of 2

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3 years ago

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Please answer ASAP WILL GIVE BRAINIEST (PLEASE NO SPAM ANSWERS)

Alexeev081 [22]

There are 11 trains containing giraffes and 7 trains containing rabbits.

<h3>Equation</h3>

An equation is an expression used to show the relationship between two or more numbers and variables.

Let x represent the number of train with giraffes and y represent the number of train with rabbits.

Hence:

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25x - 40y = 0 (1)

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25x + 40y > 500 (2)

From both equations:

A possible solution is x = 11, y = 7

There are 11 trains containing giraffes and 7 trains containing rabbits.

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3 years ago

Write the expression-3x2+2y2+5xy-2y+5x2-3y2 in simplest form A how many terms are in the simplified expression? B how many terms

natima [27]

Answer:

Step-by-step explanation:

= x²(-3 +5) +y²(2 -3) +5xy -2y

= 2x² -y² +5xy -2y

a) there are 4 terms in the simplified expression

b) 2 terms have negative coefficients (-y² and -2y)

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3 years ago

A^3+a+a^2+1 2a^2+2ab+ab^2+b^3

Vikentia [17]

$\frac{a^3+a+a^2+1}{a^3+a^2+ab^2+b^2} \cdot \frac{2a^2+2ab+ab^2+b^3}{a^3+a+a^2b+b} =\frac{a(a^2+1)+1(a^2+1)}{a^2(a+1)+b^2(a+1)} \cdot \frac{2a(a+b)+b^2(a+b)}{a(a^2+1)+b(a^2+1)} =\\\\=\frac{(a^2+1)(a+1)}{(a+1)(a^2+b^2)} \cdot \frac{(a+b)(2a+b^2)}{(a^2+1)(a+b)} = \frac{2a+b^2}{a^2+b^2}$

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3 years ago

17. The radius of a circular path is 7m. Find the cost of fencing the path if the cost per meter is Rs.35

Elis [28]

The cost of fencing the path is Rs 1539.38.

It is required to find the cost of fencing the path.

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A circle is a closed two-dimensional figure in which the set of all the points in the plane is equidistant from a given point called “centre”. The perimeter around the circle is known as the circumference.

Given that:

radius of a circular path is 7m.

Rate = Rs .35 per meter

We know that

Circumference of circle = $2\pi r$

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Circumference of circle=43.98 m

Now,

Cost = Circumference × Rate

Cost =43.98× 35

Cost = Rs 1539.38

Therefore, the cost of fencing the path is Rs 1539.38.

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2 years ago