Use the distance formula d= √ (x2-x1)^2+(y2-y1)^2 to find the length of the line with endpoints at (1,3) and (3,1)?
1 answer:
We have that
<span>line with endpoints at (1,3) and (3,1)
we know that
Applying </span><span>the distance formula
d= √ (x2-x1)^2+(y2-y1)^2
</span>d= √ (3-1)^2+(1-3)^2-------> d=√[2²+(-2)²]-----> d=√8
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