This is due tomorrow please help!!!
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The new equation of line that is perpendicular to the original that goes through the point (6, -1) in slope intercept form is
Given that original line has the equation of y = -2x + 8
We have to write a new equation that is perpendicular to the original that goes through the point (6, -1)
Let us first find slope of original line
<em><u>The slope intercept form of line is given as:</u></em>
y = mx + c ------ eqn 1
Where "m" is the slope of line and "c" is the y - intercept
On comparing the slope intercept form and given original equation, we get "m = -2"
Thus slope of original line "m" = -2
We know that product of slope of a line and slope of line perpendicular to it are always -1
slope of original line x slope of line perpendicular to it = -1
Let us find equation of line with slope m = 1/2 and passes through point (6, - 1)
Substitute and (x, y) = (6, -1) in eqn 1
<em><u>Thus the required equation of line is:</u></em>
Substitute "c" = -4 and in eqn 1
Thus the equation of line perpendicular to original line is found