The image is decomposed as follows: H1 and H2. Where original graph is Hx.
<h3>Are the images (attached) valid decompositions of the original graph?</h3>
- Yes, they are because, H1 and H1 are both sub-graphs of Hx; also
- H1 ∪ H2 = Hx
- They have no edges in common.
Hence, {H1 , H2} are valid decomposition of G.
<h3>What is a Graph Decomposition?</h3>
A decomposition of a graph Hx is a set of edge-disjoints sub graphs of H, H1, H2, ......Hn, such that UHi = Hx
See the attached for the Image Hx - Pre decomposed and the image after the graph decomposition.
Learn more about decomposition:
brainly.com/question/27883280
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Answer:
Step-by-step explanation:
y=mx+b where m=slope and b=y intercept
m=(y2-y1)/(x2-x1)
m=(-2-4)/(2+1)
m=-2 so far we have the slope
y=-2x+b, using point (2,-2) we can solve for b, the y intercept
-2=-2(2)+b
-2=-4+b
2=b so we have our line
y=-2x+2, slope is -2 and y intercept is 2
Answer:
x = ± 2i
Step-by-step explanation:
note that
= i
x² = - 12 ( take square root of both sides )
x = ±
= ±
= ± 2i
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