Answer:
I think question is not proper
you should check it again
hope your day will fine
Answer:
0.0143
Step-by-step explanation:
In this question, we are asked to use the binomial distribution to calculate the probability that 10 or fewer passengers from a sample of MIT data project sample were on American airline flights.
We proceed as follows;
The probability that a passenger was an American flight is 15.5%= 15.55/100 = 0.155
Let’s call this probability p
The probability that he/she isn’t on the flight, let’s call this q
q =1 - p= 0.845
Sample size, n = 155
P(X < A) = P(Z < (A - mean)/standard deviation)
Mean = np
= 125 x 0.155
= 19.375
Standard deviation = √npq
= √ (125 x 0.155x 0.845)
= 4.0462
P(10 or fewer passengers were on American Airline flights) = P(X \leq 10)
= P(Z < (10.5 - 19.375)/4.0462)
= P(Z < -2.19)
= 0.0143
Answer:
Step-by-step explanation:
1. 9x^5
2. 9x^6
3. 27x^5
4. 27x^6
Answer:
7.74cm ^2
Step-by-step explanation:
a=pie * r ^2
3.14*3^2=3.14*9=28.26 then you know all sides of a square are equal and 3 is half of 1 side so 6*6-=36 36-28.26=7.74
Answer:
house keeping
Step-by-step explanation:
