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dem82 [27]
4 years ago
14

Ralph has budgeted $175 for entertainment. He uses this money to go out on dates for $35 or to go out with his friends for $15.

Which budget line equation represents the situation?
A. 35x-15y=180
B. 35x+15y=180
C. (3x+5y)=180
D. 180-(35x+15y)
Mathematics
1 answer:
Stolb23 [73]4 years ago
8 0
Assuming that Ralph budgeted $180 instead of $175 entertainment. He spent $35 per date and let "x" be the number of dates he attended. He spent $15 to go out with friends and let "y" the number of times that he go out with friends.

The correct expression is the "B" which is 35x + 15y =180.
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First Class Airlines has 40 pilots for every 15 aircrafts. If they employ 240 pilots, how many aircrafts does First Class Airlin
olchik [2.2K]

Answer:

90 Aircrafts.

Step-by-step explanation:

240/40 = 6, 6 • 15 = 90. The answer would be 90 aircrafts.

8 0
3 years ago
Helppp!! 21 - 3y = -18<br> 3x+ y = -5
Ugo [173]

Answer:

(-3,4)

Step-by-step explanation:

A system of equations is given to us. The given equations are ,

\implies 2x - 3y = -18

\implies 3x + y =-5

We need to plot the graph and find the solution of the given system . For that refer to attachment . The point at which both the lines of the graph will intersect each other will be the solution of the given system of equations .

From the graph we can see that it intersect at (-3,4) . Therefore the Solution is ,

\longrightarrow \underline{\underline{ Solution = (-3,4)}}

8 0
3 years ago
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AURORKA [14]

Answer:

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4 0
3 years ago
The graph of an absolute value function opens down and has a vertex of (0, -3). The domain of the function is . The range of the
Firdavs [7]

Answer:

Domain: All real numbers

Range: y\leq -3

Step-by-step explanation:

The domain is the set of all x values. The quadratic equation continue to operate over all x-values in both directions. The domain is all real numbers.

The range is the set of all y-values. Here the quadratic begins at -3 and continues in a downward direction forever. Then range is y\leq -3

6 0
4 years ago
(WILL DO BRAINLIST)
Lynna [10]
You have a function y= \dfrac{3}{2} \left(1+\sin  \left(\dfrac{2t+1}{2}\cdot \pi\right) \right).
Since the range of the function y=\sin x is [-1,1] you have that

-1\le \sin \left(\dfrac{2t+1}{2}\cdot \pi\right)\le 1 \\ 0\le 1+\sin \left(\dfrac{2t+1}{2}\cdot \pi\right) \le 2 \\ 0\le \dfrac{3}{2} \left(1+\sin \left(\dfrac{2t+1}{2}\cdot \pi\right) \right)\le 3.
Answer: The range of given function is [0,3] and the correct choice is C.
6 0
3 years ago
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