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dem82 [27]
3 years ago
14

Ralph has budgeted $175 for entertainment. He uses this money to go out on dates for $35 or to go out with his friends for $15.

Which budget line equation represents the situation?
A. 35x-15y=180
B. 35x+15y=180
C. (3x+5y)=180
D. 180-(35x+15y)
Mathematics
1 answer:
Stolb23 [73]3 years ago
8 0
Assuming that Ralph budgeted $180 instead of $175 entertainment. He spent $35 per date and let "x" be the number of dates he attended. He spent $15 to go out with friends and let "y" the number of times that he go out with friends.

The correct expression is the "B" which is 35x + 15y =180.
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A) Work out the value of 19 + 7 divided by 2-5
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Answer: -8.66666666667

Step-by-step explanation: Do it step by step. So 19+7= 26

Then 2-5= 3

So 26 divided by -3 = -8.66666666667

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2 years ago
Write the fraction 29/7 as a repeating decimal
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Answer:

See below.

Step-by-step explanation:

7 ) 29.0

    = 4 1/7

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The 142857 repeats itself without bounds.

4 0
3 years ago
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lara31 [8.8K]
Negotiating in trade means you are bartering.
7 0
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A sample of size 200 will be taken at random from an infinite population. given that the population proportion is 0.60, the prob
Musya8 [376]

Let p be the population proportion. <span>
We have p=0.60, n=200 and we are asked to find P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60 and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is considered to be large and hence the sampling distribution of sample proportion-^p will follow the z standard normal distribution. Hence this sampling distribution will have the mean of all sample proportions- U^p = p = 0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] = √[0.60*(1-0.60)/200] = √0.0012. 
So, the probability that the sample proportion is less than 0.58 
= P(^p<0.58) 
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0... 
= P(z<-0.58) 
= P(z<0) - P(-0.58<z<0) 
= 0.5 - 0.2190 
= 0.281 
<span>So, there is 0.281 or 28.1% probability that the sample proportion is less than 0.58. </span>

4 0
3 years ago
The water reaches a max height when the horizontal distance from the firefighter to the building is approximately __m. Round to
elena-s [515]

The horizontal distance from the firefighter at which the maximum height of water occurs is 10.83m

<u>Explanation:</u>

Given:

h(x) = -0.026x² + 0.563x + 3

where,

h(x) is the height of the water

Initial speed, u = 14m/s

angle, θ = 30°

(a)

Horizontal distance = ?

h(x) = ax² + bx + c

the vertex is found at x = -b/2a

where,

x = distance to the maximum height

As compared to the equation given:

a = -0.026

b = 0.563

Thus,

x = \frac{-0.563}{2 X -0.026} \\\\x = \frac{0.563}{0.052}\\ \\x = 10.83m

Therefore, horizontal distance from the firefighter at which the maximum height of water occurs is 10.83m

3 0
3 years ago
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