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photoshop1234 [79]
3 years ago
9

-1 2/3 / (-2 1/5) solve this for me please &&' thank you

Mathematics
1 answer:
dangina [55]3 years ago
3 0
Start by putting into improper fractions.
- 1 2/3 = - 5/3
- 2 1/5 = - 11/5

Now stack the fractions like this.

\frac{ \frac{-5}{3} }{ \frac{-11}{5} }

Here's the key part (or one of them). Cancel the minus signs. Since there are 2 of them they become a plus.

\frac{ \frac{5}{3} }  { \frac{11}{5} }

Now invert the 11/5. That means turn it upside down. Put the 5 in the numerator and 11 in the denominator. Multiply by it by the top fraction.

\frac{5}{3} * \frac{5}{11}

When you do this, you just multiply top by top and bottom by bottom
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(2+ 3)(8-13) write answer in simplest radical form.<br>​
denis-greek [22]

Looks like a good question, using the mathematical term of "radical."

7 0
4 years ago
Read 2 more answers
What is 3b(8)+(-2)(7c);for b=2,c=3
BabaBlast [244]

Answer:

6

Step-by-step explanation:

6*8=48

-2*21= -42

48+ -42 = 6

8 0
4 years ago
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give an example of a convergent infinite series whose sum equal 3/5. explain how you know your series converges and write out wo
krek1111 [17]

Answer:

The series 1/5, 2/15, 4/45, 8/135... converges and sums up to 3/5

Step-by-step explanation:

Consider the infinite geometric series

1/5, 2/15, 4/45, 8/135...

With first term, a=1/5

common ratio, r = ⅔

The series converge because the common ratio, |r|<1.

The sum to infinity of a geometric series, S= a/(1-r)

S= 1/5 ÷ (1-⅔) = 1/5 ÷ 1/3 = 3/5

Therefore, the geometric series 1/5, 2/15, 4/45, 8/135... sums up to 3/5.

5 0
3 years ago
Whats the answer of 39 + 156 1/5
Rudiy27
Is 156 1/5 a mixed number? if so, your answer should be 70.2
you have to convert the mixed number into a decimal. 

156 1/5= 31.2

now add the them both,
39+31.2=70.2 

hope this helps....
4 0
3 years ago
What is the range of possible
olya-2409 [2.1K]

Answer:

4<C <10

Step-by-step explanation:

Theorem: Given a triangle with sides A, B and C the sum of the lengths of any two sides of a triangle must be greater than the third side:

1.  A+B>C

2.  B +C >A

3.  A+C>B

Thus given two sides of A=3 and B=7 C can be:

7 −3<C < 7+3

C range  

4<C <10

8 0
3 years ago
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