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zaharov [31]
3 years ago
7

the table below shows a proportional relationship fill in the missing values servings 12 ,4 16 ,8 ounces 21 ? ? ? please help wi

ll maemrk brainest explain ​
Mathematics
1 answer:
Karolina [17]3 years ago
3 0

Answer: the missing values are 7, 28 and 14

Step-by-step explanation:

In a proportional relationship, there is a constant relationship between the given variables. Thus, for any change in the value of one variable, there is a corresponding change in the value of the other variable.

The table shows a proportional relationship between values of servings

12 ,4 16 ,8

and values of ounces

21 ? ? ?

Let the missing values be x, y and z

Therefore,

21/12 = x/4

1.75 = x/4

x = 4 × 1.75

x = 7

21/12 = y/16

y = 16 × 1.75 = 28

21/12 = z/8

z = 1.75 × 8 = 14

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Add and Subtract Rational Expressions with a Common Denominator
Sladkaya [172]

Answer:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}

Step-by-step explanation:

<u>Simplifying Rational Expressions</u>

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}

Operating on the numerators:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}

Removing parentheses:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}

Simplifying:

\boxed{\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}}

The expression cannot be further simplified.

7 0
3 years ago
A student wants to check six websites. Four of the websites are social and two are school-related. After checking just two sites
mash [69]

The approximate probability that she checked a social website first, then a school-related website is 0.267.

First step is to calculate the Total number of websites

Total number of websites=Number of school websites+Number of social websites

Total number of websites=2+4

Total number of websites=6

Second step

Probability of checking the social website first

Probability of checking social website=Number of social websites/Total number of websites

Probability of checking social website= 4/6

Third step

Since one social website is checked which means that she is left with 3 social website and 2 school websites

Total number websites=2+3

Total number websites=5

Forth step

Probability of checking social website=Number of school websites/Total number websites

Probability of checking social website=2/5

Fifth step

Probability= 4/6 x 2/5 = 0.2666

Probability=0.267(Approximately)

Inconclusion the approximate probability that she checked a social website first, then a school-related website is 0.267.

Learn more about probability here:brainly.com/question/25688842

6 0
3 years ago
Can someone explain how we solve this problem
riadik2000 [5.3K]
It is look so x=? so if it was 2 then it would be
2-1 = 2+1
_______          which is wrong so that's how to do it which is x?
2+5 = 2-7 

the answer is 1/7 so ya its D.1/7 :) hope i helped
4 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!! Why would someone choose to use a graphing calculator to solve a system of linear equatio
ohaa [14]

Answer:

A graphing calculator is more accurate than graphing by hand. If the slope and/or y-intercept is a fraction or decimal, it is more difficult to accurately graph by hand.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Jimmy's backyard is rectangle that is 18 5/6 yards long and 10 2/5 yards wide Jim buy sod in pieces that are 1 1/3 yard long and
g100num [7]

Answer:

111 pieces of soda

Step-by-step explanation:

step 1

Find the area of the rectangular backyard

The area of the rectangular backyard is equal to

A=LW

where

L=18\frac{5}{6}\ yd=\frac{18*6+5}{6}=\frac{113}{6}\ yd

W=10\frac{2}{5}\ yd=\frac{10*5+2}{5}=\frac{52}{5}\ yd

substitute

A=(\frac{113}{6})(\frac{52}{5})

A=\frac{5,876}{30}\ yd^2

step 2

Find the area of one piece of sod

The area of the rectangular piece of sod is

A=LW

where

L=1\frac{1}{3}\ yd=\frac{1*3+1}{3}=\frac{4}{3}\ yd

W=1\frac{1}{3}\ yd=\frac{1*3+1}{3}=\frac{4}{3}\ yd

substitute

A=(\frac{4}{3})^2\\\\A=\frac{16}{9}\ yd^2

step 3

Find the pieces of sod needed

To find out how many whole pieces of sod will Jim need to buy to cover his backyard, divide the area of the backyard by the area of one piece of soda

so

\frac{5,876}{30} : \frac{16}{9}=\frac{52,884}{480}=110.175

Round up

111 pieces of soda

8 0
3 years ago
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