Question

Draw the graph of the line that is parallel to y−3=1/3(x+2) and goes through the point (1,7).

Answer 1

Answer:

Step-by-step explanation:

First find the slope of the given line.

y - 3 = 1/3(x+2)

y - 3 = (1/3)x + 2/3

y = (1/3)x + 2/3 + 3

y = (1/3)x + 11/3

Compare it with

y = mx + c

We get m = 1/3

As the parallel lines have same slope, the slope of the second line will also be m= 1/3

y = mx + c

y = (1/3)x + c

As this line goes through the point (1,7), substitute it in the equation:

7 = (1/3)1 + c

7 = 1/3 + c

c = 7 - 1/3

c = 21-1/3

c = 20/3

The equation of the line is found by substituting m = 1/3 and c = 20/3 into the general equation

y = mx + c

y = (1/3)x + 20/3

Graph of the equation is shown