Draw the graph of the line that is parallel to y−3=1/3(x+2) and goes through the point (1,7).
1 answer:
Answer:
Step-by-step explanation:
First find the slope of the given line.
y - 3 = 1/3(x+2)
y - 3 = (1/3)x + 2/3
y = (1/3)x + 2/3 + 3
y = (1/3)x + 11/3
Compare it with
y = mx + c
We get m = 1/3
As the parallel lines have same slope, the slope of the second line will also be m= 1/3
y = mx + c
y = (1/3)x + c
As this line goes through the point (1,7), substitute it in the equation:
7 = (1/3)1 + c
7 = 1/3 + c
c = 7 - 1/3
c = 21-1/3
c = 20/3
The equation of the line is found by substituting m = 1/3 and c = 20/3 into the general equation
y = mx + c
y = (1/3)x + 20/3
Graph of the equation is shown
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Step-by-step explanation:
You need to translate all the points to the right 3 and up 6
Therefore, you are going to use this formula:
(x,y) ⇾ (x + 3, y + 6)
This is the same format as the previous problem, if you have noticed.
Using this, plug in each coordinate, starting with P (5, -1)
(5, -1) ⇾ ( 5 + 3, -1 + 6)
(5, -1) ⇾ ( 8, 5 )
P = (8, 5)
Now point Q, (0, 8)
(0, 8) ⇾ (0 + 3, 8 + 6)
(0, 8) ⇾ ( 3, 14 )
Q = (3, 14)
And last but not least, the point R, (7, 5)
(7, 5) ⇾ (7 + 3, 5 + 6)
(7, 5) ⇾ ( 10, 11 )
R = (10, 11)
Therefore, P = (8, 5), Q
= (3, 14), R
= (10, 11) is your answer. This is the 4th option or D.
Hope this for you to understand this a bit more! =D