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3 years ago

What is number 2 need help kinda confused

Mathematics

1 answer:

maxonik [38]3 years ago

7 0

Since 60 minutes are in 1 hour, we can do (0.08 km/1 min)*(60min/1 hour) and cross out the minutes, getting (0.08*60 km)/(1 hour)= 4.8km/1 hour. Since 1.61 kilometers are in 1 mile, we can multiply the equation by 1mile/1.61 km (since they are equal) and cross out the km to get 4.8*1.61miles/1 hour= \
7.728mi/1 hour. Since it's closer to 8 than 5, 3, or 2, D is right

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I have 8 boxes of chocolate i eat 3 chocolates from each box i now have 72 chocolates in total

nydimaria [60]

Answer: there were 12 chocolates in each box. (Originally, before any got eaten)

Step-by-step explanation: let x represent the total amount of chocolates in each box.

8x - 3(8) = 72

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8x = 96 divide both sides by 8

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Find the midpoint of segment AB given. A (-3, 2) and B (3, -2)

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Hard math problems that equal 8

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3 years ago

Suppose that six individuals are interested in taking part in a study relating BMI to a number of health outcomes. The following

posledela

Answer:

a) Mean = 27.65

Median = 27.645

b) Relative Frequency = 33.33%

Step-by-step explanation:

We are given the following data set:

25.78, 21.06, 36.54, 29.51, 18.96, 34.05

a) Mean and Median

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{165.9}{6} = 27.65$

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

Sorted data: 18.96, 21.06, 25.78, 29.51, 34.05, 36.54

$\text{Median} = \displaystyle\frac{25.78 +29.51}{2} = 27.645$

b) BMI above 30 is considered obese

Frequency of obese in the given sample = 2

Relative Frequency =

$\displaystyle\frac{\text{Frequency of obese}}{\text{Total number}} = \frac{2}{6} = 0.3333 = 33.33\%$

5 0

3 years ago