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vaieri [72.5K]
3 years ago
6

What is number 2 need help kinda confused

Mathematics
1 answer:
maxonik [38]3 years ago
7 0
Since 60 minutes are in 1 hour, we can do (0.08 km/1 min)*(60min/1 hour) and cross out the minutes, getting (0.08*60 km)/(1 hour)= 4.8km/1 hour. Since 1.61 kilometers are in 1 mile, we can multiply the equation by 1mile/1.61 km (since they are equal) and cross out the km to get 4.8*1.61miles/1 hour= \
7.728mi/1 hour. Since it's closer to 8 than 5, 3, or 2, D is right
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Karen had 3 apples. she ate 2. how many will she have left​
Vadim26 [7]

Answer:1

Step-by-step explanation:

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3 years ago
Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case
olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

(c) The probability that neither Dave nor Mike will show up is 0.25.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = Dave will show up.

<em>M</em> =  Mike will show up.

Given:

P(D^{c})=0.55\\P(M^{c})=0.45

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

                                                   =1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0
4 years ago
Read 2 more answers
Find the value of x (URGENT/GIVING BRAINLIEST)
natta225 [31]

Answer:

B)10

Step-by-step explanation:

Because this is a right angle(indicated by the red box) the total measure should be 90°.

And based on that we say 5X +40=90

Subtract 40 from both sides to get 5x=50

And then divide both sides by 5 to get x=10

7 0
3 years ago
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Aleksandr [31]
You can't really determine the amount of computers from this question, they're obviously not going to have one computer for everyone so half third, or even a fourth of the school population
3 0
3 years ago
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Please help with 11c!?
Contact [7]

Answer:

"To the nearest year, it would be about 9 years"

Step-by-step explanation:

11c)

This is compound growth problem. It goes by the formula:

F=P(1+r)^t

Where

F is the future amount

P is the present (initial) amount

r is the rate of growth, in decimal

t is the time in years

Given,

P = 20,000

r = 8% = 8/100 = 0.08

F = double of initial amount = 2 * 20,000 = 40,000

We need to find t:

F=P(1+r)^t\\40,000=20,000(1+0.08)^t\\2=(1.08)^t

To solve exponentials, we can take Natural Log (Ln) of both sides:

2=(1.08)^t\\Ln(2)=Ln((1.08)^t)

Using the rule shown below we can simplify and solve:

Ln(a^b)=bLn(a)

We can write:

Ln(2)=Ln((1.08)^t)\\Ln(2)=tLn(1.08)\\t=\frac{Ln(2)}{Ln(1.08)}\\t=9.0064

To the nearest year, that would be about 9 years

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