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4 years ago

Is 4/6 greater than or less than 6/10

Mathematics

2 answers:

AleksandrR [38]4 years ago

8 0

Because it said it was and i said it was

erica [24]4 years ago

6 0

Yes, 4\6 is greater than 6\10 because if you change them they will have a common denominator.

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If x + y = –10 and x - y = 2, what is the value of x?

luda_lava [24]

Answer:

y -10

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Step-by-step explanation:

5 0

3 years ago

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Aliun [14]

It’s c i know bc i had the question

3 0

3 years ago

June made a design with 6 equal tiles.One tile is yellow 2 tiles are blue and 3 tiles are purple. what fraction of the tiles are

lana66690 [7]

we know that

The fraction of each tile color can be found by dividing the number of tiles for each tile by the total number of tiles, then simplifying the fraction if possible.

Let

N----------> total number of tiles

Y---------> number of yellow tiles

B--------> number of blue tiles

P--------> number of purple tiles

we have

$N=6\\ Y=1\\ B=2\\ P=3$

1) Find the fraction of yellow tiles

we know that

the fraction of yellow tiles is equal to

$Y/N$

substitute the values

$1/6$

2) Find the fraction of purple tiles

we know that

the fraction of purple tiles is equal to

$P/N$

substitute the values

$3/6$

3) Find the fraction of yellow tiles or purple tiles

we know that

the fraction of yellow tiles or purple tiles is equal to

$(Y/N)+(P/N)=(1/6)+(3/6)=4/6=2/3$

therefore

the answer is

$2/3$

3 0

4 years ago

Read 2 more answers

Find the dy/dx xy=(x+y)^4

JulijaS [17]

Answer:

dy/dx = (4 (x + y)^3 - y) / ( x - 4(x + y)^3).

Step-by-step explanation:

xy = (x + y)^4

Using implicit differentiation:

x dy/dx + y*1 = 4 (x + y)^3 * (1 + dy/dx)

x dy/dx + y = 4 (x + y)^3 + 4 dy/dx (x + y)^3

x dy/dx - 4 dy/dx (x + y)^3 = 4 (x + y)^3 - y

dy/dx( x - 4(x + y)^3) = 4 (x + y)^3 - y

dy/dx = (4 (x + y)^3 - y) / ( x - 4(x + y)^3)

8 0

4 years ago

what are the x-coordinates for the maximum points in the function f(x) = 4 cos(2x- pi) from x = 0 to x= 2 pi?

julsineya [31]

Answer:

$\frac{\pi }{2}$ and $\frac{3\pi }{2}$

Step-by-step explanation:

To find the max points we need to take the derivative of the function and then find the critical values.

First we take the derivative:

$f(x) = 4cos(2x-\pi )\\f'(x)=-4sin(2x-\pi )(2)\\f'(x)=-8sin(2x-\pi )\\$

Now we need to find when f'(x)=0 to find the critical values.

$0=-8sin(2x-\pi )\\0=sin(2x-\pi )\\sin^{-1}0=2x-\pi \\0=2x-\pi \\\pi =2x\\\frac{\pi }{2} =x$

The critical values will be

$\frac{\pi }{2} n$ for any integer n

between 0 and 2 pi, the critical values will be

$0, \frac{\pi }{2} ,\pi ,\frac{3\pi }{2},2\pi$

We can determine if these are minimums or maximums by using the second derivative test.

So we need to take the second derivative;

$f'(x)=-8sin(2x-\pi )\\f''(x) = -8cos(2x-\pi )(2)\\f''(x)=-16cos(2x-\pi)$

We need to see if the second derivative is positive or negative to determine if it is a max or min.

$f''(0) = 16\\f''(\frac{\pi}{2})=-16\\f''(\pi )=16\\f''(\frac{2\pi}{3}) = -16\\$

Since the second derivative is negative at

$\frac{\pi }{2}$ and $\frac{3\pi }{2}$

we know both of those are the x-values of maximums.

5 0

4 years ago