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Nesterboy [21]
3 years ago
15

Of course, you don't know what the dropdowns are, so, I'll tell you.

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
5 0

Part A

4 < 5 < 9 is given to us. Apply the square root to each term to end up with this inequality: sqrt(4) < sqrt(5) < sqrt(9)

So sqrt(5) is between <u>sqrt(4)</u> and <u>sqrt(9)</u>

-------------------

Part B

Simplify those two mentioned square roots

sqrt(4) = sqrt(2^2) = 2

sqrt(9) = sqrt(3^2) = 3

Therefore, sqrt(5) is also between <u>2</u> and <u>3</u>

We can see this through using a calculator: sqrt(5) = 2.23607 approximately

-----------------

Part C

We can now say:

2 < sqrt(5) < 3

Multiply all three sides by 6

6*2 < 6*sqrt(5) < 6*3

So the expression 6*sqrt(5) is between <u>6 x 2</u> and <u>6 x 3</u>

Sure enough, a calculator confirms this

6*sqrt(5) = 13.416408

since 6*2 = 12 and 6*3 = 18. We see that 13.416 is between 12 and 18.

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Step-by-step explanation:

5(5n+2)+(3-2n)

Distribute

25n + 10 +3 -2n

Combine like terms

25n -2n  + 10+3

23n +13

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3 years ago
After the drama club sold 100 tickets to a show, it had $300 in profit. After the next show, it had sold a total of 200 tickets
Alinara [238K]

Answer:


Option a :  y-300 = 4(x - 100)


Step-by-step explanation:

Given :

The drama club sold 100 tickets to a show, it had $300 in profit.

The next show, it had sold a total of 200 tickets and had a total of $700 profit.

To Find :  Equation models the total profit, y, based on the number of tickets sold, x

Solution :

For 100 tickets he had $300 in profit .


⇒ (x_{1} ,y_{1})=(100,300)


For 200 tickets he had $700 in profit .


⇒ (x_{2} ,y_{2})=(200,700)


We will use point slope form i.e.


y-y_{1} = m(x - x_{1}) --(A)


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m = \frac{y_{2} -y_{1} }{x_{2}-x_{1}  }


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Now, putting values in (A)


y-300 = 4(x - 100)


Thus Option a is correct i.e. y-300 = 4(x - 100)




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