The length of rectangular field is 7 m less than 4 times the width. The perimeter is 136 m. Find the width and length
2 answers:
Answer:
15 m and 53 m.
Step-by-step explanation:
Let the length of the rectangular field = x m
and width = y m
From the statement "Length is 7m less than 4 times the width"
x = 4y - 7 ----------(1)
"perimeter of the field is 136 m."
2 (x + y) = 136
x + y = 68 ---------(2)
Now we replace the value of x from equation 1 to 2
4y - 7 + y = 68
5y - 7 = 68
5y = 68 + 7 = 75
y = 15 m
From equation (2)
x + 15 = 68
x = 68 - 15
= 53 m
Therefore, length and width of the field are 15 m and 53 m.
P = 2(L + W) P = 136 L = 4W - 7 136 = 2(4W - 7 + W) 136 = 2(5W - 7) 136 = 10W - 14 136 + 14 = 10W 150 = 10W 150/10 = W 15 = W <=== width is 15 m L = 4W - 7 L = 4(15) - 7 L = 60 - 7 L = 53 <== length is 53 m
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