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Svetradugi [14.3K]
2 years ago
13

Rocio drops a ball from a height of 4 meters. Rocio observes that each time the ball bounces, it reaches a peak height which is

79% of the previous peak height, as shown at left. Which of the following equations correctly models the ball's peak height, h, in meters, after b bounces?
Mathematics
1 answer:
docker41 [41]2 years ago
4 0

The exponential equation that correctly models the ball's peak height, h, in meters, after b bounces is given by:

H(b) = 4(0.79)^b

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

A(t) = A(0)(1 - r)^t

In which:

  • A(0) is the initial value.
  • r is the decay rate, as a decimal.

In this problem:

  • Rocio drops a ball from a height of 4 meters, hence A(0) = 4.
  • Each time the ball bounces, it reaches a peak height which is 79% of the previous peak height, hence 1 - r = 0.79.

Thus, the equation is given by:

H(b) = 4(0.79)^b

More can be learned about exponential equations at brainly.com/question/25537936

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Natasha2012 [34]

Answer:B

Step-by-step explanation:

The quadratic formula can be used to solve an equation only if the highest degree in the equation is 2

7 0
3 years ago
What are the answers ?
Vadim26 [7]

Answer:

All of the answers if you consider the dashes both negative and positive, but if they are negative then its the last 3 only.

Step-by-step explanation:

5 0
3 years ago
a 5 inch tall bamboo shoot doubles in height every 3 days. if the equation, y=ab^x where x is the number of doubling periods, re
Lemur [1.5K]
X-doubling periods
Y-height of bamboo
Y=ab^x

1) make a table of values
X Y
1 5
2 10
3 20

2) write equations and substitute
5=ab^1 —> a=5/b^1 —> a=5/b
10=ab^2

Substitute into second equation

10=(5/b)*b^2
10=5b^2/b
10=5b
b=2

Substitute back in

b=2
10=a*2^2
10=4a
a=5/2

End equation:
Y=5/2*2^x


3 0
3 years ago
Which scenario could NOT be described by the following graph?
beks73 [17]

Answer:

D. the total distance a vehicle travels as it goes up a hill and then maintains a constant rate of speed at the top.

even if the distance increases the graph should rise up.

5 0
3 years ago
Read 2 more answers
Keegan is printing and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total
Katarina [22]

Answer:

t-shirts: 2790

profit: $12209

Step-by-step explanation:

Given  the function:

p(x) = -x³ + 4x² + x

we want to maximize it.

The following criteria must be satisfied at the maximum:

dp/dx = 0

d²p/dx² < 0

dp/dx = -3x² + 8x + 1 = 0

Using quadratic formula:

x = \frac{-b \pm \sqrt{b^2 -4(a)(c)}}{2(a)}

x = \frac{-8 \pm \sqrt{8^2 -4(-3)(1)}}{2(-3)}

x = \frac{-8 \pm 8.72}{-6}

x_1 = \frac{-8 + 8.72}{-6}

x_1 = -0.12

x_2 = \frac{-8 - 8.72}{-6}

x_2 = 2.79

d²p/dx² = -6x + 8

d²p/dx² at x = -0.12: -6(-0.12) + 8 = 8.72 > 0

d²p/dx² at x = 2.79: -6(2.79) + 8 = -8.74 < 0

Then, he should prints 2.79 thousands, that is, 2790 t-shirts to make maximum profits.

Replacing into profit equation:

p(x) = -(2.79)³ + 4(2.79)² + 2.79 =  12.209

that is, $12209

3 0
3 years ago
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