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IrinaK [193]
3 years ago
14

Simplify the expression 5+4+2(-3)+7+(-5)

Mathematics
1 answer:
liberstina [14]3 years ago
4 0
Just use pemdas
(Parenthesis, exponents, multiplication, division, addition, subtraction)
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Line q has a slope of 5/3. Line r is parallel to line q. What is the slope if line r?​
seropon [69]

Answer:

The slope remains a constant m=\frac{5}{3} as it is parallel.

Explanation:

1. Line Q is defined as a slope of \frac{5}{3}; i.e. y=\frac{5}{3}

2. Line R is defined to be parallel of Line Q.

3. Line Q is linear and has no domain restrictions.

The definition of being parallel requires the same slope.

5 0
2 years ago
Chang gets paid a $50 bonus for every 100 pairs of shoes that he sells. Chang is being reinforced on a ________ schedule of rein
maksim [4K]
Tell him to stop buying shoes, you wouldnt have this questions.

that would be 1/2 :P

4 0
3 years ago
Read 2 more answers
What is the volume of the composite figure shown? (Use 3.14 for π.)
Nimfa-mama [501]
The\ volume\ of\ the\ cone:V_1=\frac{1}{3}\pi r^2 H\\(r-a\ radius;\ H-height)\\------------------\\r=7ft;\ H=7ft\\\\V_1=\frac{1}{3}\pi\cdot7^2\cdot7=\frac{1}{3}\pi\cdot343=\frac{343}{3}\pi\ (ft^2)\\-------------------\\The\ volume\ of\ the\ cylinder:V_2=\pi r^2 H\\(r-a\ radius;\ H-height)\\-------------------\\r=7ft;\ H=6ft\\\\V_2=\pi\cdot7^2\cdot6=294\pi\ (ft^3)\\------------------------\\The\ volume\ of\ the\ composite\ figure: V_F=V_1+V_2

V_F=\frac{343}{3}\pi+294\pi=\frac{343}{3}\pi+\frac{294\cdot3}{3}\pi=\frac{343}{3}\pi+\frac{882}{3}\pi=\boxed{\frac{1225}{3}\pi\ (ft^3)}\\\\\approx\frac{1225}{3}\cdot3.14}=\frac{3846.5}{3}\approx\boxed{1,282.17\ (ft^3)}\leftarrow answer
7 0
3 years ago
Please help. will give brainliest ​
vichka [17]

Answer:

  • B. The probability that the student received a grade better than C is 0.45

Step-by-step explanation:

<u>Total number of students:</u>

  • 15 + 30 + 35 + 16 + 4 = 100
<h3>Statements</h3>

A.

  • p(<D) = 4/100 = 0.04
  • 0.04 ≠ 0.2
  • Incorrect

B.

  • p(>C) = (30 + 15)/100 = 45/100 = 0.45
  • 0.45 = 0.45
  • Correct

C.

  • p(not A or B) = (100 - 15 - 30)/100 = 55/100 = 0.55
  • 0.55 ≠ 0.45
  • Incorrect

D.

  • p(B or C) = (30 + 35)/100 = 65/100 = 0.65
  • 0.65 ≠ 0.35
  • Incorrect

6 0
2 years ago
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
2 years ago
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