Answer:
![\frac{1}{4^{21} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%5E%7B21%7D%20%7D)
Step-by-step explanation:
![4^{-3*7}](https://tex.z-dn.net/?f=4%5E%7B-3%2A7%7D)
![4^{-21}](https://tex.z-dn.net/?f=4%5E%7B-21%7D)
![\frac{1}{4^{21} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%5E%7B21%7D%20%7D)
Answer:
They are equidistant from origin.
Step-by-step explanation:
Rectangle LMNO is rotated 90° clockwise around the origin to create rectangle L'M'N'O'. Which statement would best describe the relationship between points N and N'?
They are equidistant from origin.
They are midpoints of segment ON and segment O prime N prime.
They are equidistant from point O.
They are midpoints of segment LN and segment L prime N prime.
Answer: If a point with location N(x, y) is rotated 90° clockwise around the origin, the new coordinate N' is at (y, -x). The distance of the two points from the origin O(0, 0) can be calculated using:
![ON=\sqrt{(y-0)^2+(x-0)^2}=\sqrt{y^2+x^2}\\ \\ON'=\sqrt{(y-0)^2+(-x-0)^2}=\sqrt{y^2+x^2}](https://tex.z-dn.net/?f=ON%3D%5Csqrt%7B%28y-0%29%5E2%2B%28x-0%29%5E2%7D%3D%5Csqrt%7By%5E2%2Bx%5E2%7D%5C%5C%20%20%5C%5CON%27%3D%5Csqrt%7B%28y-0%29%5E2%2B%28-x-0%29%5E2%7D%3D%5Csqrt%7By%5E2%2Bx%5E2%7D)
Therefore ON = ON'. The points N and N'are equidistant from the orign
Your answer is 77!
All you really need to do is 231/3 since you need to find out how many students are in the freshman class.
U count how many students were walking then multiply it by half itself
I think it’s x>=-3
That means greater than or equal to btw :)