Answer:
2
Step-by-step explanation:
Answer:
x - y + 6 = 0
Step-by-step explanation:
In normal form of a straight line, the equation is given by
where p is the perpendicular distance of the line from the origin and
is the angle between the perpendicular line and the positive direction of the x-axis.
Here, in our case
and
Degree,
Therefore, the normal form of the straight line equation is
⇒
⇒
{Since, Cos (180 - Ф) = - Cos Ф and Sin (180 - Ф) = Sin Ф}
⇒
⇒ - x + y = 3√2 × √2 = 6
⇒ x - y + 6 = 0
So, the standard form of the equation is x - y + 6 = 0. (Answer)
12q +3r =15
3(4q +r) = 3*5
Divide both sides by 3
4q +r = 5
Time for the second one:
-4q -4r = -44
-4(q +r) = (-4)*11
Divide both sides by -4
q +r = 11
4q +r = 5
q +r = 11
Subtract the second from first equation
3q 0 = -6
3q = -6
q = -6/3 = -2
q = -2
q +r = 11
-2 +r =11
r = 11 +2
r = 13
q = -2
r = 13
Your answer is...
(-2,13)
Answer:
D= 10
Step-by-step explanation:
