Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.
(a) Complementary angles
(b) Vertical angles
(c) Supplementary angles
<u>Explanation:</u>
Complementary angles are those two angles whose sum is 90 degrees.
Supplementary angles are those two angles whose sum is 180 degrees.
Vertical angles are the angles opposite each other when two lines cross.
(a)
Angles 1 and 5 are complementary angles
(b)
Angles 3 and 5 are vertical angles
(c)
Angles 3 and 4 are supplementary angles
Answer:
3y^2 3√3y(end route) if you are simplifying, and (81y^7)^1/3 if you are rewriting it.
Step-by-step:
I know this!
Answer:
there was alot of math here but i got 10
Step-by-step explanation:
so first u add 10 and 2 u get 12 then u multiply 4 then u get 48 and divide that by 4 and then subtract 2 and get 10. hope this helped