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Zarrin [17]
4 years ago
6

Kareem lives 4/10 of a mile away from the mall. Write two equivalent that show that fraction of a mile Kareem lives from the mal

l.
Mathematics
2 answers:
Slav-nsk [51]4 years ago
6 0


8/20 and 12/30 are equivalent to 4/10.

You just have to multiply the numerator and denominator by the same number.

Hope it helps.

Can you <em><u>please please</u></em> choose mine as the brainliest answer.

I need it for me to get to the next level.

Nataliya [291]4 years ago
5 0

Answer:

\text{Equivalent fractions are } \frac{8}{20}\text{ and }\frac{2}{5}

Step-by-step explanation:

Kareem lives \frac{4}{10} of a mile away from the mall.

We need to find two equivalent fraction that show fraction of a mile Kareem lives from the mall.

We get equivalent fraction

  • multiply by the same number at numerator and denominator.
  • divide by the same number at numerator and denominator .

Using multiply we get equivalent fraction

\dfract{4}{10}=\dfrac{4\times 2}{10\times 2}=\frac{8}{20}

Using divide we get equivalent fraction

\dfract{4}{10}=\dfrac{4\div 2}{10\div 2}=\frac{2}{5}

\text{Thus, Equivalent fractions are } \frac{8}{20}\text{ and }\frac{2}{5}

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Answer:

✅The table can be represented by the equation, y = 4x + 4

✅The relation is a function.

✅The graph of the function is linear.

Step-by-step explanation:

✍️The first statement: The table can be represented by the equation, y = 4x + 4.

To check if the first statement is correct let's find the equation that can represent the table by finding the slope (m) and y-intercept (b).

Using two pairs, (1, 8) and (2, 12),

Slope = \frac{y_2 - y_1}{x_2 - x_1} = \frac{12 - 8}{2 - 1} = \frac{4}{1} = 4.

Substitute, x = 1, y = 8, and m = 4 into y = mx + b to solve for b.

Thus:

8 = (4)(1) + b

8 = 4 + b

Subtract 4 from each side

8 - 4 = b

4 = b

Plug in the values of b and m into y = mx + b.

Thus, the equation that represents the table would be:

y = 4x + 4.

✅Therefore, the first statement is correct.

✍️The second statement: The graph of the function is non-linear.

This is NOT TRUE because the equation of the function, y = 4x + 4, represents the equation of a linear graph in the slope-intercept form. When graphed, it will give us a straight line.

✍️The Third statement: The relation is a function.

This is TRUE because each input value (x-value) has exactly one output value (y-value).

✍️The Fourth statement: The rate of change is NOT constant.

This standby is NOT TRUE.

The rate of change is the slope (m) that we have calculated above to be 4. Between any two pairs, the rate of change remains 4.

Therefore, this statement is not correct.

✍️The Fifth statement: The graph of the function is linear.

This is TRUE. As stated earlier, from the equation generated, it is safe to say that the equation represents graph of a linear function. The graph will be a straight line graph.

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ludmilkaskok [199]

Answer:

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(see attached picture)

Step-by-step explanation:

The idea of solving a system of equations graphically is taht both graphs cross each other at the same point.

The problem doesn't state so, but we can find the equations of the lines that pass through the desired point by using the point-slope form of the equation and by picking any slope we wish.

The slope-intercept form of a linear equation looks like this:

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so let's use the following slopes: m_{1}=1 and m_{2}=-2. Remember, you can pick any slope you wish.

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this will be our first equation.

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so now we can plot the graphs of the given equations.

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so now my two ordered pairs are (0,10) and (-3,7) so I can plot them on my graph and connect them with a straight line. (see attached picture.)

and we can follow the same procedure for the second graph.

let's use the x=0 again so we get:

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so we plot them to get our final graph (see attached picture)

Of course, this is one of the ways in which we can solve this problem. Since they are asking us to plot the graphs and not quite finding the equations for the system of equations, you could just draw any two lines you like and the answer would be correct as long as the two lines pass through the same point.

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