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3 years ago

Estimate the measure of ∠PQR to the nearest 10 degree

Mathematics

2 answers:

svp [43]3 years ago

7 0

I’d say 30 degrees. It is bent pretty far but not too far. If it was 40 you would tell because it would be a lot closer to a 45 degree angle

timurjin [86]3 years ago

4 0

Answer: i’m just guessing but id say 45°??

Step-by-step explanation:

bc it looks like half of 90° and half of 90 is 45

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Use the distributive property of multiplication to find 5×45.<br> Hint: 45=5+40.

alexgriva [62]

Answer:

Step-by-step explanation:

Distributive property: a(b +c) = (a*b) + (a*c)

45 = 40 + 5

5* 45 = 5* (40 + 5)

= 5*40 + 5*5

= 200 + 25

= 225

8 0

2 years ago

You want to buy an MP3 player. Your Aunt paid you $20 to mow her lawn and you earn $5 each week

natka813 [3]

Answer:

1. y = 5x + 20

2. $20 the amount you saved mowing your aunt's lawn.

3. 21 weeks

Step-by-step explanation:

1. 5 is the slope because it is the rate. 20 is the y-intercept because that is how much you already have.

2. 20 because that is how much you already have.

3. Since you already have $20, you need to subtract 125 by 20 to get 105. Then you divide 105 by 5 to get 21 weeks.

6 0

3 years ago

Read 2 more answers

The interior angles of a triangle have measures (2x - 5), (4– 1), and 30°

const2013 [10]

Answer: x=26

Step-by-step explanation:

1. Write the equation 2x-5+4x-1+30=180 because all triangle angles add up to 180°

2. Simplify the equation by combining like terms. Write the equation as 6x+24=180

3. Subtract 24 from both sides. Write the equation as 6x=156.

4. Divide 156/6 and get 26. That is your answer (x=26).

8 0

3 years ago

How many real solutions does t2 + 100 = 0 have ?

forsale [732]

T=-50 is the answer........

4 0

4 years ago

Read 2 more answers

4(3n-2)^(-3/2)+1=347/343

blagie [28]

Greetings and Happy Holidays!

Solve for n.
$4(3n-2)^{\frac{-3}{2}}+1= \frac{347}{343}$

Add -1 to both sides.
$(4(3n-2)^{\frac{-3}{2}}+1)+(-1)=(\frac{347}{343})+(-1)$

$4(3n-2)^{\frac{-3}{2}}=\frac{347}{343}-1$

$4(3n-2)^{\frac{-3}{2}}=\frac{347}{343}-\frac{343}{343}$

$4(3n-2)^{\frac{-3}{2}}=\frac{4}{343}$

Divide both sides by 4
$\frac{4(3n-2)^{\frac{-3}{2}}}{4}=\frac{\frac{4}{343}}{4}$

$\frac{4(3n-2)^{\frac{-3}{2}}}{4}=\frac{4}{343}(\frac{1}{4})$

$\frac{4(3n-2)^{\frac{-3}{2}}}{4}=\frac{4}{1372}$

$\frac{4(3n-2)^{\frac{-3}{2}}}{4}=\frac{1}{343}$

$(3n-2)^{\frac{-3}{2}}=\frac{1}{343}$

Solve the Exponent.
$((3n-2)^{\frac{-3}{2}})^{\frac{2}{-3}} =\frac{1}{343}^{\frac{2}{-3}}$

$3n-2=49$

Add 2 to both sides.
$(3n-2)+2=(49)+2$

$3n=51$

Divide both sides by 3.
$\frac{3n}{3}= \frac{51}{3}$

$n=17$

The Answer Is:
$\left[\begin{array}{ccc}n=17\end{array}\right]$

Hope this helped!
-Benjamin

5 0

3 years ago