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STatiana [176]
3 years ago
8

Please help me ASAP. Many Thanks

Mathematics
1 answer:
tresset_1 [31]3 years ago
5 0
You have to make the fraction into an integer. the simplest version of a ratio involves the smallest possible integers. therefore, 5:2.5 will equal 10:5 (you multiply both sides by 2). 10:5 cancels down to 2:1. hope this helped :)
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Help me please :/ do any of y’all know the answer?
andriy [413]

Answer:

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Step-by-step explanation:

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3 years ago
For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!
Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

x^2-2x-(c+4)=0.

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic ax^2+bx+d, the discriminant is \sqrt{b^2-4ad}.

(The discriminant is more commonly known as \sqrt{b^2-4ac}, but I changed the variable since we already have a c in the quadratic given.)

In the quadratic above, we have a=1, b=-2, and d=-(c+4). Plugging this into the formula for the discriminant, we have

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Using the distributive property to expand and simplifying, the expression becomes

\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.

Setting the discriminant equal to 0 gives

2\sqrt{c+5}=0.

We can then solve the equation as usual: first, divide by 2 on both sides:

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and subtracting 5 from both sides, we have

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3 0
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lesya [120]
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kkurt [141]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
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