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Nitella [24]
3 years ago
9

Where should 0.3% be placed in the Venn diagram?

Mathematics
1 answer:
Anit [1.1K]3 years ago
7 0

Answer:

bottom

Step-by-step explanation:

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What is the radius of the circle?
Stolb23 [73]

Answer:

8×ED=3×15

ED=45/8

the radius is the half of the diameter

so its 45/16

3 0
3 years ago
Read 2 more answers
a catering service offers 6 appetizers, 10 main courses, and 8 desserts. A banquet committee is to select 2 appetizers, 3 main c
S_A_V [24]

There are two different answers that you could be looking for.
You might be asking how many different meals can be served at the banquet,
or you might be asking literally how many 'ways' there are to put meals together.

I'm going to answer both questions.  Here's how to understand the difference:

Say you have ten stones, and you tell me "I'll let you pick out two stones
and take them home.  How many ways can this be done ?"

For my first choice, I can pick any one of 10 stones.  For each of those . . .
I can pick any one of the 9 remaining stones for my second choice.
So the total number of 'ways' to pick out two stones is  (10 x 9) = 90 ways.

But let's look at 2 of those ways:
   -- If I pick stone-A first and then pick stone-G, I go home with 'A' and 'G'.
   -- If I pick stone-G first and then pick stone-A, I still go home with 'A' and 'G'.
There are two possible ways to pick the same pair.
In fact, there are two possible ways to pick <em><u>every</u></em> pair.
So there are 90 <em><u>ways</u></em> to pick a pair, but only 45 different pairs.

That's the reason for the difference between the number of <em><u>ways</u></em> the
committee can make their selections, and the number of different <em><u>meals</u></em>
they can put together for the banquet.

So now here's the answer to the question:

-- Two appetizers can be selected in (6 x 5) = 30 ways.
(But each pair can be selected in 2 of those ways,
so there are only 15 possible different pairs.)

-- Three main courses can be selected in (10 x 9 x 8) = 720 ways.
(But each trio can be selected in 3*2=6 of those ways,
so there are only 120 possible different trios.)

-- Two desserts can be selected in (8 x 7) = 56 ways.
(But each pair of them can be selected in 2 of those ways,
so there are only 28 possible different pairs.)

-- The whole line-up can be selected in (30 x 720 x 56) = <em>1,209,600 ways</em>.

But the number of different meals will be  (30 x 720 x 56) / (2 x 6 x 2) =

                                                                   (15 x 120 x 28) =  <em><u>50,400 meals</u></em>.



5 0
3 years ago
Sahil got 28 questions right on the math test. Angelina got 7 more wrong answers than Sahil. There where 40 questions on the tes
Mariana [72]
[A+7= 28] is the correct equation I believe, though I may be wrong.
7 0
3 years ago
Read 2 more answers
What is the slope of (3,5) and (1,3)
Maksim231197 [3]
(3,5)....x1 = 3 and y1 = 5
(1,3)....x2 = 1 and y2 = 3

slope formula : (y2 - y1) / (x2 - x1)
slope = (3 - 5) / (1 - 3) = -2/-2 = 1 <== slope is 1
7 0
3 years ago
Read 2 more answers
Choose whether it's always, sometimes, never 
Keith_Richards [23]

Answer: An integer added to an integer is an integer, this statement is always true. A polynomial subtracted from a polynomial is a polynomial, this statement is always true. A polynomial divided by a polynomial is a polynomial, this statement is sometimes true. A polynomial multiplied by a polynomial is a polynomial, this statement is always true.

Explanation:

1)

The closure property of integer states that the addition, subtraction and multiplication is integers is always an integer.

If a\in Z\text{ and }b\in Z, then a+b\in Z.

Therefore, an integer added to an integer is an integer, this statement is always true.

2)

A polynomial is in the form of,

p(x)=a_nx^n+a_{n-1}x^{x-1}+...+a_1x+a_0

Where a_n,a_{n-1},...,a_1,a_0 are constant coefficient.

When we subtract the two polynomial then the resultant is also a polynomial form.

Therefore, a polynomial subtracted from a polynomial is a polynomial, this statement is always true.

3)

If a polynomial divided by a polynomial  then it may or may not be a polynomial.

If the degree of numerator polynomial is higher than the degree of denominator polynomial then it may be a polynomial.

For example:

f(x)=x^2-2x+5x-10 \text{ and } g(x)=x-2

Then \frac{f(x)}{g(x)}=x^2+5, which a polynomial.

If the degree of numerator polynomial is less than the degree of denominator polynomial then it is a rational function.

For example:

f(x)=x^2-2x+5x-10 \text{ and } g(x)=x-2

Then \frac{g(x)}{f(x)}=\frac{1}{x^2+5}, which a not a polynomial.

Therefore, a polynomial divided by a polynomial is a polynomial, this statement is sometimes true.

4)

As we know a polynomial is in the form of,

p(x)=a_nx^n+a_{n-1}x^{x-1}+...+a_1x+a_0

Where a_n,a_{n-1},...,a_1,a_0 are constant coefficient.

When we multiply the two polynomial, the degree of the resultand function is addition of degree of both polyminals and the resultant is also a polynomial form.

Therefore, a polynomial subtracted from a polynomial is a polynomial, this statement is always true.

3 0
3 years ago
Read 2 more answers
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