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coldgirl [10]
4 years ago
9

Earl runs 75 meters in 30 seconds .How many meters does Earl run per second​

Mathematics
1 answer:
belka [17]4 years ago
6 0

Answer:

2.5 meters per second

Step-by-step explanation:

75/30 = 2.5

I'd choose 25 because the person who wrote the answers probably forgot to add decimal points

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8 sundaes

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What is the time 5 minutes before noon
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11:55

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Julio bought 12 bulbs of jumbo garlic for $11.88. How many bulbs of jumbo garlic can Anjali buy if she has $3.96?
Molodets [167]

Answer:

Anjali can buy 4 bulbs of jumbo garlic if she has $3.96.

Step-by-step explanation:

To calculate how many bulbs of jumbo garlic Anjali can buy with $3.96, we must first calculate the unit rate of the jumbo garlic. Julio buying 12 bulbs of jumbo garlic for $11.88 can be represented as:

\frac{11.88}{12}

Divide the fraction by \frac{12}{12} to calculate the unit rate:

\frac{.99cents}{1bulb}

So if each bulb of garlic costs $0.99, which we can think of as being $1.00 at the moment, we could figure that Anjali's $3.96 would be closer to $4 than it is to $3, so let's multiply the unit rate by \frac{4}{4}:

\frac{.99}{1} × \frac{4}{4}=

\frac{3.96}{4}

Therefore, Anjali can buy 4 bulbs of jumbo garlic if she has $3.96.

_

Check your work by dividing \frac{3.96}{4} by \frac{4}{4} to see if you will get your initial unit rate:

\frac{3.96}{4} ÷ \frac{4}{4} =

\frac{0.99}{1}

Therefore, our solution is correct!

7 0
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A student takes a driving test until it is passed.
Leya [2.2K]

Answer:

The probability that the test is taken an even number of times is 0.30.

Step-by-step explanation:

The probability that a student passes the driving test at any attempt is,

<em>p</em> = 4/7.

The event of a student passing in any attempt is independent of each other.

The probability that the test is taken an even number of times is:

P (even number of tests) = P (Passing in the 2nd attempt)

                                                  + P (Passing in the 4th attempt)

                                                       + P (Passing in the 6th attempt) ...

If a student passed in the 2nd attempt it implies that he failed in the first.

Then,  P (Passing in the 2nd attempt) = (\frac{3}{7}) \times (\frac{4}{7})

Similarly, P (Passing in the 4th attempt) = (\frac{3}{7})^{3} \times (\frac{4}{7}), since he failed in the first 3 attempts.

And so on.

Compute the probability of an even number of tests as follows:

P (even number of tests) = (\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...

The result follows a Geometric progression for infinite values.

The sum of infinite GP is:

S=\frac{a}{1-r^{2}}

The probability is:

P (even number of tests) = (\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...

                                          =\frac{(\frac{3}{7})(\frac{4}{7} ) }{1-(\frac{3}{7})^{2}}\\=\frac{12}{49}\times\frac{49}{40}\\  =\frac{12}{40}\\ =0.30

Thus, the probability that the test is taken an even number of times is 0.30.

7 0
3 years ago
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