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coldgirl [10]
3 years ago
9

Earl runs 75 meters in 30 seconds .How many meters does Earl run per second​

Mathematics
1 answer:
belka [17]3 years ago
6 0

Answer:

2.5 meters per second

Step-by-step explanation:

75/30 = 2.5

I'd choose 25 because the person who wrote the answers probably forgot to add decimal points

You might be interested in
The regression equation for predicting number of speeding tickets (Y) from information about driver age (X) is Y = -.065(X) + 5.
ivolga24 [154]

Answer:

c. 4.27

Step-by-step explanation:

We have been given the regression equation of for predicting number of speeding tickets (Y) from information about driver age (X) as Y=-0.065(X)+5.57.

To find the predicted number of tickets for a twenty-year-old, we will substitute X=20 in our given equation.

Y=-0.065(20)+5.57

Y=-1.3+5.57

Y=4.27

Therefore, the predicted number of tickets for a twenty-year-old would be 4.27 tickets.

6 0
3 years ago
3
ser-zykov [4K]

Answer: D. Subtracting 9 from each side

Step-by-step explanation:

Always start with numbers without variables first before doing anything with x. And make sure one side must not equal 0 unless you're doing polynomials.

5 0
3 years ago
The length of the base of a triangle is twice its height. if the area of the triangle is 225 square kilometers, find the height
Anon25 [30]
Let
x----------> length of the base
y----------> height

we know that
[the area of triangle]=[length of the base]*[height]/2
x=2y
A=225 km²
225=x*y/2---------> 225=(2y)*y/2-----> y²=225--------> y=15 km
x=2y--------> x=2*15------> x=30 km

the answer is
the height is 15 km

3 0
3 years ago
When individuals in a sample of 150 were asked whether or not they supported capital punishment, the following information was o
borishaifa [10]

Answer:

\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The expected values for all the categories is :

E_i =\frac{150}{3}=50

And then the statistic would be given by:

\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4

And the best option would be:

b. 4

Step-by-step explanation:

For this problem we have the following observed values:

Yes 40 No 60 No Opinion 50

And we want to test the following hypothesis:

Null hypothesis: All the opinions are uniformly distributed

Alternative hypothesis: Not All the opinions are uniformly distributed

And for this case the statistic would be given by:

\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The expected values for all the categories is :

E_i =\frac{150}{3}=50

And then the statistic would be given by:

\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4

And the best option would be:

b. 4

7 0
3 years ago
You might need:
Oduvanchick [21]

Answer:

The maximum possible number of mosquitoes is 25 millions

Step-by-step explanation:

Let

m(x) -----> the number of mosquitoes in Minneapolis, Minnesota (in millions of mosquitoes)

x ----> the rainfall in centimeters

we have

m(x)=-(x-5)^{2} +25

This is a quadratic equation (vertical parabola) open downward

The vertex is the maximum

we know that

The maximum possible number of mosquitoes is equal to the y-coordinate of the vertex

Find out the coordinate of the vertex

The general equation of a vertical parabola in vertex form is equal to

y=a(x-h)^{2} +k

where

a is a coefficient

(h,k) is the vertex

so

In this problem

a=-1 (open downward)

(h,k)=(5,25)

The y-coordinate is 25

therefore

The maximum possible number of mosquitoes is 25 millions

5 0
3 years ago
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