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3 years ago

Earl runs 75 meters in 30 seconds .How many meters does Earl run per second

Mathematics

1 answer:

belka [17]3 years ago

6 0

Answer:

2.5 meters per second

Step-by-step explanation:

75/30 = 2.5

I'd choose 25 because the person who wrote the answers probably forgot to add decimal points

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The regression equation for predicting number of speeding tickets (Y) from information about driver age (X) is Y = -.065(X) + 5.

ivolga24 [154]

Answer:

c. 4.27

Step-by-step explanation:

We have been given the regression equation of for predicting number of speeding tickets (Y) from information about driver age (X) as $Y=-0.065(X)+5.57$ .

To find the predicted number of tickets for a twenty-year-old, we will substitute $X=20$ in our given equation.

$Y=-0.065(20)+5.57$

$Y=-1.3+5.57$

$Y=4.27$

Therefore, the predicted number of tickets for a twenty-year-old would be 4.27 tickets.

6 0

3 years ago

ser-zykov [4K]

Answer: D. Subtracting 9 from each side

Step-by-step explanation:

Always start with numbers without variables first before doing anything with x. And make sure one side must not equal 0 unless you're doing polynomials.

5 0

3 years ago

The length of the base of a triangle is twice its height. if the area of the triangle is 225 square kilometers, find the height

Anon25 [30]

Let
x----------> length of the base
y----------> height

we know that
[the area of triangle]=[length of the base]*[height]/2
x=2y
A=225 km²
225=x*y/2---------> 225=(2y)*y/2-----> y²=225--------> y=15 km
x=2y--------> x=2*15------> x=30 km

the answer is
the height is 15 km

3 0

3 years ago

When individuals in a sample of 150 were asked whether or not they supported capital punishment, the following information was o

borishaifa [10]

Answer:

$\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The expected values for all the categories is :

$E_i =\frac{150}{3}=50$

And then the statistic would be given by:

$\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4$

And the best option would be:

b. 4

Step-by-step explanation:

For this problem we have the following observed values:

Yes 40 No 60 No Opinion 50

And we want to test the following hypothesis:

Null hypothesis: All the opinions are uniformly distributed

Alternative hypothesis: Not All the opinions are uniformly distributed

And for this case the statistic would be given by:

$\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The expected values for all the categories is :

$E_i =\frac{150}{3}=50$

And then the statistic would be given by:

$\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4$

And the best option would be:

b. 4

7 0

3 years ago

You might need:

Oduvanchick [21]

Answer:

The maximum possible number of mosquitoes is 25 millions

Step-by-step explanation:

Let

m(x) -----> the number of mosquitoes in Minneapolis, Minnesota (in millions of mosquitoes)

x ----> the rainfall in centimeters

we have

$m(x)=-(x-5)^{2} +25$

This is a quadratic equation (vertical parabola) open downward

The vertex is the maximum

we know that

The maximum possible number of mosquitoes is equal to the y-coordinate of the vertex

Find out the coordinate of the vertex

The general equation of a vertical parabola in vertex form is equal to

$y=a(x-h)^{2} +k$

where

a is a coefficient

(h,k) is the vertex

In this problem

a=-1 (open downward)

(h,k)=(5,25)

The y-coordinate is 25

therefore

The maximum possible number of mosquitoes is 25 millions

5 0

3 years ago

Earl runs 75 meters in 30 seconds .How many meters does Earl run per second​

Earl runs 75 meters in 30 seconds .How many meters does Earl run per second