Given BD and AC is a diameter of the circle:
We need to find the following:
1. measure of the arc BA
So,
the measure of the minor arc BA = 44
The measure of the major arc BA = 360 - 44 = 316
2. the measure of the arc ACB = 360 - 44 = 316
3. The arc BCD is a semicircle of the circle
So, the measure of the arc BCD = 180
129 degrees you just add DCE and ECF together
450 g in 2:13
<u>Total proportion asked for </u>=2+13=15
<u>Now comparing g with ratio, or whatever </u>
450/15=30g 
Therefore 1 in ratio depicts of 30g
So final answer = 
More to know, daily bit of knowledge: The Binomial Theorem:
I believe it is x=55. I could be wrong lol
We turn -5,12 into polar coordinates. It's a Pythagorean Triple so
r = 13 Ф=arctan(-12/5) + 180° ( in the second quadrant )
so -5 = 13 cos Ф, 12 = 13 sin Ф
12 sin x - 5 cos x = 6.5
13 sinФ sin x + 13 cos Ф cos x = 6.5
13 cos(x - Ф) = 6.5
cos(x - Ф) = 1/2
cos(x - Ф) = cos 60°
x - Ф = ± 60° + 360° k integer k
x = Ф ± 60° + 360° k
x = 180° + arctan(-12/5) ± 60° + 360° k
That's the exact answer;
x ≈ 180° - 67.38° ± 60° + 360° k
x ≈ 122.62° ± 60° + 360° k
x ≈ { 62.62°, 182.62°} + 360° k, integer k
