Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]
It's hard to tell where one set ends and the next starts. I think it's
A. 25, 36, 44, 51, 62, 77
B. 3, 3, 3, 7, 9, 9, 10, 14
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.
A. 25, 36, 44, 51, 62, 77
That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.
B. 3, 3, 3, 7, 9, 9, 10, 14
Average around 7, sigma around 4, within 2 sigma, seems ok.
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
Average around 20, sigma around 8, that 39 is hanging out there past two sigma. Let's reserve judgement and compare to the next one.
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Average around 74, sigma 8, seems very tight.
I guess we conclude C has the outlier 39. That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.
Answer:
(8,-3)
Step-by-step explanation:
The given parabola is
We factor -3 from the first two terms to get:
Add and subtract the square of half the coefficient of x
We simplify to get:
We compare this to y=a(x-h)²+k,
The vertex is (h,k)=(8,-3)
Answer:
200.96in
Step-by-step explanation:
I used this equation with 3.14 as pi
Area = 1/2 * 2radius*pi * radius
Answer:
x = 34°
Step-by-step explanation:
The chord- chord angle x is half the sum of the measures of the arcs intercepted by the angle and its vertical angle.
x = 
( AB + CD ) = (45 + 23)° = 0.5 × 68° = 34°
