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3 years ago

7

A scale of a classroom. The scale in the drawing is 2 inches represent 9 feet. The actual length is 36 feet. What is the length

of the classroom.

1 answer:

Oksanka [162]3 years ago

5 0

The answer to the question is 36 feet. However, I think you may want to know the scale of the length on the drawing. That would be 6 inches.

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Pls help me with this, please thank you!!

Aleonysh [2.5K]

Mr.chen drove 23 miles south from where he started. 3.25×50=162.5 is what you have to do first because it said that he drove north for 3.25 hours and each hour he drives for 50 miles. Then you have to subtract 162.5 from 185.5 so that you get how far he drove from where he started. 185.5 - 162.5= 23. So he drove 23 miles south from where he started. I hope this helps.

4 0

3 years ago

What is 4n 8 equivalent to

aev [14]

<span>Answer:

n = 32/3 = 10.667</span>

8 0

3 years ago

8n-9m=6-3m in standard form

Klio2033 [76]

Answer:

-6m+8n-6=0

Step-by-step explanation:

3 0

3 years ago

Help plz I don't understand and SHOW ME HOW YOU GOT IT!!!!!!!!

AysviL [449]

(48-7)x(56+19)
First of all you need to work out the brackets.
48-7=41
56+19=75
This turns the question to: 41x75
When multiply decimals you can split the numbers up into the tens and units.
40x70=2800
40x5=200
1x70=70
1x5=5
2800+200+70+5= 3075
This answer would be 3075.

6 0

3 years ago

The lifetime of a certain type of battery is normally distributed with mean value 15 hours and standard deviation 1 hour. There

KIM [24]

Answer:

If the lifetime of batteries in the packet is 40.83 hours or more then, it exceeds for 5% of all packages.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 15

Standard Deviation, σ = 1

Sample size = 4

Total lifetime of 4 batteries = 40 hours

We are given that the distribution of lifetime is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling:

$\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{1}{\sqrt4} = 0.5$

We have to find the value of x such that the probability is 0.05

P(X > x) = 0.05

$P( X > x) = P( z > \displaystyle\frac{x - 40}{0.5})=0.05$

$= 1 -P( z \leq \displaystyle\frac{x - 40}{0.5})=0.05$

$=P( z \leq \displaystyle\frac{x - 40}{0.5})=0.95$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 40}{0.5} = 1.64\\x = 40.825 \approx 40.83$

Hence, if the lifetime of batteries in the packet is 40.83 hours or more then, it exceeds for 5% of all packages.

8 0

4 years ago