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2 years ago

7

Pls help me with this, please thank you!!

1 answer:

Aleonysh [2.5K]2 years ago

4 0

Mr.chen drove 23 miles south from where he started. 3.25×50=162.5 is what you have to do first because it said that he drove north for 3.25 hours and each hour he drives for 50 miles. Then you have to subtract 162.5 from 185.5 so that you get how far he drove from where he started. 185.5 - 162.5= 23. So he drove 23 miles south from where he started. I hope this helps.

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$t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723$

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Step-by-step explanation:

Information provided

$\bar X=5.97$ represent the sample mean for the length

$s=0.4$ represent the sample standard deviation

$n=93$ sample size

$\mu_o =6$ represent the value that we want to test

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:

Null hypothesis: $\mu = 6$

Alternative hypothesis: $\mu \neq 6$

since we don't know the population deviation the statistic is:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing in formula (1) we got:

$t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723$

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P value

The degrees of freedom are given by:

$df=n-1=93-1=92$

Since is a two tailed test the p value would be:

$p_v =2*P(t_{(92)}$

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

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