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tresset_1 [31]
3 years ago
14

PLEASE HELP I GIVE THANKS

Mathematics
1 answer:
lara [203]3 years ago
6 0
V=lwh\\\\
V=14.1\cdot6.1\cdot8\\
V=688.08 \text { cm}^3 \Rightarrow A
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Solve your answer in the simplest form or as a mixed number. <br>5 7/9 + 4 5/6​
ss7ja [257]

Answer:

10 11/18

Step-by-step explanation:

5 42/54   4 45/54

9 87/54

10 33/54

10 11/18

pleas give me a brainliest if this helped

5 0
3 years ago
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Your Turn: Using the figure, a
Hatshy [7]
We are given:
\frac{a}{c} = \frac{d}{a}

First step is to get rid of fractions. We start by multiplying both sides by a.
\frac{a}{c} = \frac{d}{a} /*a \\

Now we cancel a on right side and we multiply both sides by c.
\frac{ a^{2}}{c} = \frac{da}{a} /*c \\ \frac{ a^{2}c}{c} = dc

After canceling c on the right side we are left with:
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8 0
3 years ago
1.)
VashaNatasha [74]

Answer:

1. z = -15

2. p = 7

3. h = -11

4. t = 14

5. q = 12

Step-by-step explanation:

1.

\frac{z}{-5}+1=4

Add -1 both sides,

\frac{z}{-5}+1-1=4-1\\\frac{z}{-5}=3

Multiply both sides by -5,

\frac{z}{-5}\times-5=3\times-5\\z=-15

2.

Distribute 3 in p+2 and then add -6p and -6 both sides.

3(p+2)=6p-15\\3\times p+3\times2 = 6p-15\\3p+6=6p-15\\3p-6p=-15-6\\-3p=-21\\p=\frac{-21}{-3}=7

3.

\frac{h-7}{2}=3(h+8)

Multiply both sides by 2,

\frac{h-7}{2}\times2=3(h+8)\times2\\h-7=6(h+8)\\h-7=6h+48

Add -6h and 7 both sides,

h-6h-7+7=6h-6h+48+7\\-5h=55\\h=\frac{55}{-5}\\h=-11

4.

4t+2-5=3(t+7)-9\\4t-3=3t+21-9\\4t-3=3t+12

Add -3t and 3 both sides.

4t-3t-3+3=3t-3t+12+3\\t=15

5.

2(q-4)=4(q-8)\\2q-8=4q-32

Add -2q and 8 both sides.

2q-8-4q+8=4q-4q-32+8\\-2q=-24\\q=\frac{-24}{-2}\\q=12

Therefore,

1. z = -15

2. p = 7

3. h = -11

4. t = 14

5. q = 12

4 0
4 years ago
What mathematical concepts did René Descartes start
frozen [14]

Answer:

Algebra and geometry

is this what you were looking for?

3 0
3 years ago
Read 2 more answers
Round 24 3/7up to the nearest whole number
tatyana61 [14]

Answer:

24

Step-by-step explanation:

I hope this helps, and have a great day! :D

7 0
3 years ago
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