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HACTEHA [7]
3 years ago
14

At the beginning of a population study, the population of a large city was 1.65 million people. Three years later, the populatio

n was 1.74 million people. Assume that population grows according to an uninhibited exponential growth model.
What would be the population of the city 5 years after the start of the population study?

A. 2.1518
B. 1.7683
C. 1.8027
D. 1.8843
F. None of the Above
Mathematics
1 answer:
Maksim231197 [3]3 years ago
6 0

Answer:

C. 1.8027

Step-by-step explanation:

The exponential population growth model is given by:

P(t) = P_{0}e^{rt}

In which P(t) is the population after t years, P_{0} is the initial population and r is the growth rate.

At the beginning of a population study, the population of a large city was 1.65 million people. Three years later, the population was 1.74 million people.

This means that P_{0} = 1.65, P(3) = 1.74

Applying this to the equation, we find r. So

P(t) = P_{0}e^{rt}

1.74 = 1.65e^{3r}

e^{3r} = \frac{1.74}{1.65}

e^{3r} = 1.0545

Applying ln to both sides

\ln{e^{3r}} = \ln{1.0545}

3r = \ln{1.0545}

r = \frac{\ln{1.0545}}{3}

r = 0.0177

So

P(t) = 1.65e^{0.0177t}

What would be the population of the city 5 years after the start of the population study?

This is P(5).

P(t) = 1.65e^{0.0177t}

P(5) = 1.65e^{0.0177*5}

P(5) = 1.8027

So the correct answer is:

C. 1.8027

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Answer:
x=40/11 or 3 7/11

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2 years ago
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If a is the average (arithmetic mean) of 4x and 7, b is the average of 5x and 6, and c is the average of 3x and 11, what is the
Debora [2.8K]

Answer:

2x+4

Step-by-step explanation:

Given that a is the average (arithmetic mean) of 4x and 7, b is the average of 5x and 6, and c is the average of 3x and 11

By definition of arithmetic mean,

we have a=\frac{4x+7}{2} \\b=\frac{5x+6}{2} \\c=\frac{3x+11}{2}

Let us calculate sum of a,b,c in terms of x

a+b+c = \frac{4x+7+5x+6+3x+11}{2} \\=6x+12

Average = sum/3 = \frac{6x+12}{3} =2x+4

7 0
4 years ago
PLEASE HELP ASAP
Sedbober [7]

Brainly.com

What is your question?

Middle SchoolMathematics 5+3 pts

A water park keeps track of the number of times each visitor goes down water slides during their visit . The data shows the number of times 12 visitors went down a water slide. 4, 22, 16, 10, 11, 20, 20, 12, 6, 3, 11, 1 Create a histogram of this data.

Report25.03.2017

Answers

Portal0876 · Beginner

Know the answer? Add it here!

THE BRAINLIEST ANSWER!

taskmasters

Taskmasters Ambitious

Given:

12 visitors

Visitor # Frequency of going down a water slide

1 4

2 22

3 16

4 10

5 11

6 20

7 20

8 12

9 6

10 3

11 11

12 1

Pls. see attachment for the histogram.

4 0
3 years ago
For how many real values of x is <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B120-%5Csqrt%7Bx%7D%7D%20" id="TexFormula1" title
leva [86]

A good place to start is to set \sqrt{x} to y. That would mean we are looking for \sqrt{120-y} to be an integer. Clearly, y\leq 120, because if y were greater the part under the radical would be a negative, making the radical an imaginary number, not an integer. Also note that since \sqrt{x} is a radical, it only outputs values from [0,\infty], which means y is on the closed interval: [0,120].

With that, we don't really have to consider y anymore, since we know the interval that \sqrt{x} is on.

Now, we don't even have to find the x values. Note that only 11 perfect squares lie on the interval [0,120], which means there are at most 11 numbers that x can be which make the radical an integer. All of the perfect squares are easily constructed. We can say that if k is an arbitrary integer between 0 and 11 then:

\sqrt{120-\sqrt{x}}=k \implies \\ \sqrt{x}=k^2-120 \implies\\ x=(k^2-120)^2

Which is strictly positive so we know for sure that all 11 numbers on the closed interval will yield a valid x that makes the radical an integer.

5 0
3 years ago
At the movie theatre, child admission is S5.20 and adult admission is $8.30. On Tuesday, 156 tickets were sold for a total sales
Annette [7]

Answer:

So, 89 Adult tickets were sold.

Step-by-step explanation:

So, we first name our variables, say, a for number of adult tickets, and c for child tickets.

Then we write our system of equations, first the total $ sale:

5.2c + 8.3a = 1087.10

Then we write the 2nd equation, the total number of tickets:

c + a = 156

Now, we can solve the system:

We do have different methods, let's to by subsitution.

make some change to the 2nd equation, to make c the subject: c = 156 - a

Now we plug that into the 1st equation:

5.2(156 - a) + 8.3a = 1087.10

811.2 - 5.2a + 8.3a = 1087.10

811.2 + 3.1a = 1087.10

3.1a = 275.9

a = 89

8 0
3 years ago
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