Suppose an isosceles triangle ABC has A = 45° and b = c = 4. What is the length of a^2?
1 answer:
Since b = c, the angles B and C are congruent. 180 - 45 = 135 135/2 = =67.5 A = 45 B = 67.5 C = 67.5 a = ? b = 4 c = 4 Since we know two sides and all three angles, we can use the law of sines to find a. b/sin B = a/sin A 4/(sin 67.5) = a/(sin 45) a = 4(sin 45)/(sin 67.5) a^2 = (4(sin 45)/(sin 67.5))^2 a^2 = 9.37
You might be interested in
Answer:
5
Step-by-step explanation:
This is because she cannot buy 5.91 pairs of shoes and she doesn't have enough money to buy exactly 6, so you must round it down to 5.
The solving is : 4x = 336 x= 84
The answer is 156 there is 156 combinations
oml, this is false . truely false !!
hope this helps ya! :)
This is probably way overcomplicated but i cant remember how to do it w = n l = 2n+1 w*l = 66 n(2n+1) = 66 2n^2 + n =66 2n^2 + n - 66 = 0 using quadratic equation n = 11/2 width = 11/2 = 5.5 length = 11 + 1 = 12