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Triss [41]
3 years ago
9

Suppose an isosceles triangle ABC has A = 45° and b = c = 4. What is the length of a^2?

Mathematics
1 answer:
Mila [183]3 years ago
4 0
Since b = c, the angles B and C are congruent.
180 - 45 = 135
135/2 = =67.5

A = 45
B = 67.5
C = 67.5
a = ?
b = 4
c = 4

Since we know two sides and all three angles, we can use the law of sines to find a.

b/sin B = a/sin A

4/(sin 67.5) = a/(sin 45)

a = 4(sin 45)/(sin 67.5)

a^2 = (4(sin 45)/(sin 67.5))^2

a^2 = 9.37
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C = 0.3*-2.7 = -0.81

Hope it helps:)
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3 years ago
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A homeowner is installing a swimming pool. You have been asked to install a circuit to operate a 600-watt underwater light and a
insens350 [35]

Answer:

The answer is given below

Step-by-step explanation:

The loads in the circuit are continuous duty, so the circuit can only loaded to 80% of its current rating.

Calculate 80% current rating of the circuit breaker.

Icb = [ 80/100] (20 A)

     =  (O.8) (20 A )

     = 16 A

Now we assume that the value of supply voltage is 120 V

Now we will calculate current flows via under water light which will be taken as  Load 1

<em>Ii = </em>500 W/120 V

  = 4.167 A

Current via the circulating pump which will be taken as Load 2 IS 8.5 A

<em>I = </em>load1 + load 2

<em>    = 4.167 A + 8.5 A</em>

<em>   = 12.67 A</em>

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3 years ago
Is anyone good at geometry if so Can you please help me <br><br> NO LINKS
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Answer:

a.

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Step-by-step explanation:

8 0
3 years ago
-(-4)(-6)-3/5(10+15)/1/3
Ksenya-84 [330]

Answer:

-29

solving steps:

\sf \hookrightarrow -\left(-4\right)\left(-6\right)-3/5\left(10+15\right)/1/3

\sf \hookrightarrow  -\left(-4\right)\left(-6\right)-3/5\cdot \:25/1/3

\sf \hookrightarrow  -24-3/5\cdot \:25/1/3

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3 0
2 years ago
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zhuklara [117]
I'll go out on a limb and suppose you're given the matrix

\mathbf A=\begin{bmatrix}a&b&c\\d&e&f\\g&h&i\end{bmatrix}

and you're asked to find the determinant of \mathbf B, where

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and given that \det\mathbf A=2.

There are two properties of the determinant that come into play here:

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(2) Adding/subtracting rows does not change the value of the determinant.

Taken together, we have that

\det\mathbf B=-4\det\mathbf A=-8
5 0
3 years ago
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