An inequality is solved by more than one value - usually an interval, or a union of intervals.
In this case, we have:

Add 14 to both sides:

Divide both sides by 12:

The figure has reflective symmetry about a line if that line divides the figure in two similar parts, which are reflections of one another.
Notice that the two figures formed when the shape is divided by line k are not similar, since one has 7 vertices and the other just 4.
Notice that the two figures formed when the shape is divided by line m are not similar, since one has 7 vertices and the other just 4.
The line l divides the figure in two shape, one is a trapezoid and the other isn't.
Only line n divides the figure in two similar shapes.
Therefore, the correct choice is B) n only.
The temperature was in the range of 10-13 on 7 of the days.
Give it the weight of the middle of the range = 11.5 for 7 times = 80.5
The temperature was in the range of 14-17 on 9 of the days.
Give it the weight of the middle of the range = 15.5 for 9 times = 139.5
The temperature was in the range of 18-21 on 16 of the days.
Give it the weight of the middle of the range = 19.5 for 16 times = 312
The temperature was in the range of 22-25 on 22 of the days.
Give it the weight of the middle of the range = 23.5 for 22 times = 517
The temperature was in the range of 26-29 on 6 of the days.
Give it the weight of the middle of the range = 27.5 for 6 times = 165
Total weight for all ranges = (80.5 + 139.5 + 312 + 517 + 165) = 1,214
Total number of days = 60
Estimated mean temperature = (1,214) / (60) = <u>20.23°C </u>
The average rate of change of the function over −2 ≤ x ≤ 2 is 1/2
<h3>How to determine the average rate of change?</h3>
The function is given as:

The interval is given as:
−2 ≤ x ≤ 2
Calculate h(2) and h(-2)

h(2) = -3

h(-2) = -5
The average rate of change is then calculated as:

This gives

Evaluate
m = 1/2
Hence, the average rate of change of the function over −2 ≤ x ≤ 2 is 1/2
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<u>Complete question</u>

What is the average rate of change of h over the interval −2 ≤ x ≤ 2