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Mama L [17]
3 years ago
10

Tina is saving to buy a notebook computer. She has two options. The first option is to put $500 away initially and save $30 ever

y month. The second option
is to put $200 away initially and save $50 every month. After how many months would Tina save the same amount using either option?How much would she save with either option?
Mathematics
1 answer:
Jlenok [28]3 years ago
3 0
First option:
y=money saved
x=number of months

y=30x+500

Second option:

y=50x+200

We have this system of equations:

y=30x+500
y=50x+200

We can solve this system of equations by equalization method
30x+500=50x+200
30x-50x=200-500
-20x=-300
x=-300/-20
x=15

so;
y=30x+500
y=30(15)+500
y=450+500
y=950

Answer; after 15 months, she would save the same amount using either option, the amount saved in either option will be $950. 
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Area of square = 9 mm2<br> Perimeter of square=
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the perimeter of the square is 12 mm

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in 2012, the population of a city was 63,000. by 2017, the population was reduced to approximately 54,100. identify any equation
Akimi4 [234]

Answer:

<em></em>f(x) = 63000(0.97)^x<em></em>

<em></em>

Step-by-step explanation:

Given

f(0) = 63000 ---x = 0, in 2012

f(5) = 54100 -- x = 5, in 2017

Required

Select all possible equations

Because there is a reduction in the population, as time increases; the rate must be less than 1.

An exponential function is represented as:

f(x) = ab^x

Where

b = rate

rate > 1 in options (a) and (b) i.e. 1.03

This implies that (a) and (b) cannot be true

For option (c), we have:

f(x) = 63000(0.97)^x

Set x = 0

f(0) = 63000(0.97)^0 = 63000*1=63000\\

Set x = 5

f(5) = 63000(0.97)^5 = 63000*0.8587=54098.1 \approx 54100

<em>This is true because the calculated values of f(0) and f(5) correspond to the given values</em>

For option (d), we have:

f(x) = 52477(0.97)^x

Set x = 0

f(0) = 52477(0.97)^0 - 52477* 1 = 52477

<em>This is false because the calculated value of f(0) does not correspond to the given value</em>

For option (e), we have:

f(x) = 63000(0.97)^\frac{1}{5x}

Set x = 0

f(0) = 63000(0.97)^\frac{1}{5*0} = 63000(0.97)^\frac{1}{0} =undefined

<em>This is false because the f(x) is not undefined at x = 0</em>

For option (f), we have:

f(x) = 52477(0.97)^{5x

Set x = 0

f(0) = 52477(0.97)^{5*0} = 52477(0.97)^0 =52477*1= 52477

<em>This is false because the calculated value of f(0) does not correspond to the given value</em>

<em>From the computations above, only (c) </em>f(x) = 63000(0.97)^x<em> is true</em>

4 0
3 years ago
12.33 to the nearest tenth
ivann1987 [24]
12.3 is the answer i think 
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A number cube labeled 1 to 6 is rolled 450 times. Which is the best prediction for the number of times that the number cube will
Vedmedyk [2.9K]
Haha, I don't think those answers belong to the question asked :P

The probability of rolling less than 3 is 2/6=1/3

So if you rolled 450 times you should expect to roll less than 3:

450(1/3)=150 times.
3 0
3 years ago
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