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Vladimir79 [104]
4 years ago
5

What is 12.374 rounded to the nearest tenth

Mathematics
2 answers:
Oksanka [162]4 years ago
5 0
The answer is 12.4 hope it help

abruzzese [7]4 years ago
4 0
Its 12.4 because 7 is greatee than 5
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8 0
3 years ago
A rectangle has dimensions of 15 centimeters long and 16 meters wide what is the area of the rectangle
Brrunno [24]
240 is the answer to your question just multiply them

6 0
4 years ago
Solve the inequality.
frutty [35]

Answer:

\boxed{\boxed{\sf x>-7}}

Step-by-step explanation:

\sf -5x-7

Add 7 to both sides:

  • \sf -5x-7+7
  • \sf -5x

Multiply both sides by -1:

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Divide both sides by 5:

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3 0
3 years ago
The area of a rectangle is 45 cm2. Two squares are constructed such that two adjacent sides of the rectangle are each also the s
Zielflug [23.3K]

Answer:

The lengths of sides of squares are 5 cm and 9 cm.

Step-by-step explanation:

Let the sides of rectangle be x and y .

Area of rectangle = Length × Breadth

Given : Area of rectangle = 45 cm².

⇒ x × y  = 45  

⇒ x=\frac{45}{y}  ........(1)

Two squares are constructed such that two adjacent sides of the rectangle

so squares have side x and y .

Area of square = side × side

Area of square with side x = x²

Area of square with side y = y²

Also, The combined area of the two squares is 106 cm².

⇒ x² + y² = 106

From (1) put value of x , we get,

(\frac{45}{y})^2+y^2=106

Solving for y ,

(\frac{45}{y})^2+y^2=106  

2025+y^4=106y^2  

y^4-106y^2+2025=0  

y^4-81y^2-25y^2+2025=0  

y^2(y^2-81)-25(y^2-81)=0  

(y^2-25)(y^2-81)=0

y^2-81=0 or y^2-25=0    

on solving we get y = 5 and y = 9

Also, x can be find by putting in (1),

⇒ x=\frac{45}{5}=9 and ⇒ x=\frac{45}{9}=5  

⇒ x = 9 and x = 5

Thus, lengths of sides of squares are 5 cm and 9 cm.

6 0
4 years ago
Read 2 more answers
What is the result of (x^2 – 10x) – (–5x^2 + x)?
Tanzania [10]

Answer:

( {x}^{2}  - 10x) - ( - 5 {x}^{2}  + x) \\  {x}^{2}  - 10x + 5 {x}^{2}  - x \\  \boxed{6 {x}^{2}  - 11x}

<h3>(6x²-11x) is the right answer.</h3>
6 0
3 years ago
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