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ludmilkaskok [199]
2 years ago
7

Write an EQUATION for the nth term of each arithmetic sequence 15,13,11,9,...

Mathematics
1 answer:
Nataliya [291]2 years ago
8 0
First you have to organize it like this
1 : 2 : 3 : 4
15 : 13: 11 : 9
If the sequence is decreasing then the nth term equation will start with a negative.try to see which will work -1,-2,-3,-4...
The answer is: x= -3n + 17
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The product of a binomial and trinomial is x^3+3x^2-x+2x^2+6x-2 which expression is equivalent to this product after it has been
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Answer: First option.

Step-by-step explanation:

You know that the product obtained by multiplying a binomial and a trinomial is:

x^3+3x^2-x+2x^2+6x-2

Then, in order to simplify this product, it is necessary to add the like terms.

Therefore, the expression that is equivalent to this product after it has been fully simplified is:

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2 years ago
PLS ANSWER ASAP FIRST ONE TO DO SO GETS BRAINLIEST
Marta_Voda [28]

Answer:

Carmen can make 10\frac{5}{16} full servings.

Step-by-step explanation:

Given : Carmen mixes 3\frac{1}{2} cups of water with 3\frac{3}{8}  cups of juice to make punch.

Total quantity of punch Carmen made = total cup of water + cup of juice she mixes

Total quantity of punch Carmen made = 3\frac{1}{2}+3\frac{3}{8}

Solving , we get,

Total quantity of punch Carmen made = \frac{7}{2}+\frac{27}{8}

taking LCM(2,8) = 8 , we get,

Total quantity of punch Carmen made = \frac{28+27}{8}=\frac{55}{8}

Also, given She pours \frac{2}{3} cup servings of punch.

Thus, \frac{2}{3} cup of mixture makes 1 serving cup.

Using unitary method,

In unitary method we first find the value of a single quantity and then multiply it with the desired quantity.

1 cup of mixture makes \frac{3}{2} serving cup.

\frac{55}{8} cup makes = \frac{3}{2}\times\frac{55}{8}

\frac{55}{8} cup makes = \frac{165}{16}=10\frac{5}{16}

Thus, She can make 10\frac{5}{16} full servings.


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What is the GCF of: 18k and 15k3<br> and how do you get that answer
Solnce55 [7]

Answer:

List all the factors for 18,15 to find the common factors. The common factors for 18,15 are 1,3 . The GCF for the numerical part is 3 . The factor for k1 is k itself.

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Answer:

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---------------------------------------------

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