1) 1,2,3,4,5,6,7
2) -3,-2,-1,0,1,2,3,4,5,6,7
3)-3,-2,-1
4)1,2,3,4
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The general equation of a circle is x^2 + y^2 = r^2. Here we know that the circle passes thru two points: (-3,2) and (1,5). Given that a third point on the circle is (-7, ? ), find the y-coordinate of this third point.
Subst. the known values (of the first point) into this equation: (-3)^2 + (2)^2 = r^2. Then 9 + 4 = 13 = r^2.
Let's check this. Assuming that the equation of this specific circle is
x^2 + y^2 = r^2 = 13, the point (1,5) must satisfy it.
(1)^2 + (5)^2 = 13 is not true, unfortunately.
(1)^2 + (5)^2 = 1 + 25 = 26 (very different from 13).
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1/2 of 40 is 20, and the question says 1/4 of the REMAINING cookies, and 1/4 of 20 is 5. There are 3/4 left, or 15 cookies. I hope this helps!
Answer:
The slope is 2.5 and the y-intercept is 15.
Step-by-step explanation:
The slope is 2.5 and the y-intercept is 15.
m= slope
b= y-intercept
Answer:
No real
solution
Step-by-step explanation:
Firstly, let us check if we would be having a real solution
We start by rewriting the equation
We have this as;
8x^2 -25x + 24 = 0
We proceed to get the discriminant
Mathematically, we have this as;
D = b^2 - 4ac
b is the coefficient of x which is -25
a is the coefficient of x^2 which is 8
c is the last number which is 24
So we have;
D = (-25)^2 - 4(8)(24)
D = 625 - 768 = -143
Since the value of the discriminant is negative, there cannot be real roots
What we have as solution are complex roots
