The quotient rule is
d(u/v) = (u dv - v du) / u2
d(u/v) can written as
d( u (1/v) )
Using the product rule and chain rule
d( u (1/v)) = u d(1/v) + (1/v) du
= u (-1/v2) dv + (!/v) du
= (u dv - v du) / u2
You would multiply the power by the powers of both exponents
2 × 3 = 6 so a^6
3 × 4 = 12 so b^12
Answer is
a^6b^12
84 I'm sure it's that I did it before
